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3 years ago

( 2 x - 3 ) ( 7 x + 4) polynomials

Mathematics

1 answer:

Taya2010 [7]3 years ago

6 0

Answer:

14x-12

Step-by-step explanation:

Simplify (2x-3)(7x+4).

Expand the brackets. Remember brackets mean to multiply.

We multiply the 2x and the 7x to get 14x and we multiply the -3 by 4 to get -12 as shown below;

(2x-3)(7x+4)

14x-12

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What is the result if 3x-9 is evaluated when x = -5?

Anton [14]

Answer:

Step-by-step explanation:

I wonder if it is the minus that is causing the problem?

Let x = - 5

3*(-5) - 9

-15 - 9

This is a money question. If you are 15 dollars in debt and you spend another 9, where are you? (In the company of the American government. They do this all the time).

- 15 - 9 = - 24

5 0

3 years ago

7g + 11 subtracted from 12

BlackZzzverrR [31]

A subtracted from b means b-a

7g+11 subtracted from 12 means 12-(7g+11)=12-1(7g+11)=12-7g-11=12-11-7g=1-7g

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3 years ago

What is the GCF of 48x4 and 44x5

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3 years ago

Graph the function and analyze it for domain, range, continuity, increasing or decreaseing behavior, symmetry, boundedness, extr

Sunny_sXe [5.5K]

Answer:

$f(x) = 3 \cdot 0.2^x$

Step-by-step explanation:

$f(x) = 3 \cdot 0.2^x$

Domain of f: "What values of x can we plug into this equation?" This makes sense for all real numbers so the domain is $\mathbb{R}$

Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore $(0, \infty)$ .

Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.

Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.

Symmetry: It is clear to see the graph of f(x) has no symmetry.

Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe $f(x-1) > f(x)$ for all x in the domain.

The function is however bounded below by 0: no value of x in the domain exists which satisfies $f(x) < 0$ .

Extrema: As far as I can tell, there are no turning points on the curve. (Is this what you mean by extrema?)

Asymptotes: Contrary to the curve's appearance, there are no vertical asymtotes for this curve. The negative-x portion of the curve is just growing so quickly it appears to look like an asymptote. There is a value of f(x) for all x<0. There is however a horizontal asymtote: $y=0$ .