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Hunter-Best [27]

3 years ago

13

A family of 2 adults and e children goes to a play. admission costs $8 per adult and $5 per child. what expression would show th

e tot admission cost for the family?

2 answers:

Slav-nsk [51]3 years ago

8 0

a*8 +e*5 = cost of admission

2*8 +e5 = cost

16+5e = cost

TiliK225 [7]3 years ago

4 0

Answer:

I assume you mean three children? In that case:

Step-by-step explanation:

(2x8)+(3x5)

=16+15

=31

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NEED HELP NEED HELP please if you know show me how you got the answer

OLEGan [10]

Answer:

It says to Graph y = 1/2x - 4

So equation y = 1/2x - 4

this corresponds to slope intercept form which is y = mx + b

M = slope = rise / run

B = y - intercept

First, start at the origin, (0,0)

Then go down 4, you should now be on the coordinate (0,4)

Now we need to use the slope.

The slope is 1 / 2, this means rise 1, run 2 (in this case 2 to the right because it is positive)

So, start at (0 , 4) and go up 1 unit then 2 to the right, then place a dot, keep repeating until you meet the end of the paper.

Then do the opposite so that you can graph the other side.

Down 1 and 2 to the left.

4 0

3 years ago

Read 2 more answers

Use the order of operations to simplify -5 + 3(7.2 - 3.2)

mafiozo [28]

Answer:

7 (Seven)

Step-by-step explanation:

4 0

3 years ago

The base of a triangle is shrinking at a rate of 11 cm/s and the height of the triangle is increasing at a rate of 11 cm/s. Find

Mumz [18]

Answer:

the rate of changes of the area of the triangle

$\frac{dA}{dt} = -11 cm^2 /sec$

Step-by-step explanation:

<u>Explanation</u> :-

The area of triangle( A) = $\frac{1}{2} base X height$ ..........(1)

Let 'b' be the base and 'l' be the length of the triangle

The base of a triangle is shrinking( means decreasing) at a rate of 11 cm/s

that is $\frac{db}{dt} = -11cm/sec$

The height of a triangle is increasing at a rate of 11 cm/s

that is $\frac{dh}{dt} = 11cm/sec$

Given h= 10cm and b = 8cm

<u>The rate of change of triangle </u>

applying uv formula $\frac{d(uv)}{dx} = u( \frac{dv}{dx}) + v(\frac{du}{dx} )$

Differentiating equation (1) with respective to 't'

$\frac{dA}{dt} =\frac{1}{2} ( b(\frac{dh}{dt} )+h ( \frac{db}{dt}))$

substitute all values in above equation, we get

h= 10cm , b = 8cm , $\frac{db}{dt} = -11cm/sec$ and $\frac{dh}{dt} = 11cm/sec$

$\frac{dA}{dt} = 10 (-11) + 8(11 )$

After simplification , we get

$\frac{dA}{dt} =\frac{1}{2} (-110 +88) = -11 cm^2 /sec$

7 0

4 years ago

Read 2 more answers

runners in a marathon are randomly assigned to one of ten corrals to start, and each given a green, blue, or red shirt to wear.

OleMash [197]

Answer:

There isn't a question

Step-by-step explanation:

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3 years ago

Write the following ratio using two other notations. 5/9 Use only the numbers above (not any others).

slava [35]

5:9 and 5 to 9 are two other ways to write the fraction 5/9.

I hope this helps:)

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3 years ago