$First~exercise! \\ We~ have `there ~some~ triangles.(2) \\ 1)~In~ a ~triangle~,the~degree~of~all~angles~is~180! \\ We~have~2~angles~known,so: \\ 180=x+45+56 \\ 180=101+x \\ x=79 \\ \\ Second~triangle! \\ We~have~to~find~2~angles! \\ An ~elongated`~angle~have~180~degrees! \\ 180=79+50+y \\ y=51. \\ In~the~second~triangle~,we~have~to~find~the`third~angle. \\ We~have~a~right~angle,so--\ \textgreater \ 90~degrees! \\ 180=90+51+z \\ z=39! \\ We~found~all~the~angles!(We~are`happy~now!!!~:))) \\ Second~exercise! \\ With~the~Pythagoras' Theorem,we~can~find~the~diagonal~in~this~ \\ rectangle! \\ c ^{2} =10 ^{2} +14 ^{2} \\ c ^{2} =100+196 \\ c= \sqrt{296} \\ c=17,20...$

8 0

3 years ago

Write the first six terms of the sequence.

butalik [34]

Step-by-step explanation:

1st term = -n²+6

= -(1)²+6

= -1+6

2nd term = -(2)²+6

= -4+6 = 2

3rd term= -(3)²+6

=-9+6 = -3

4th term= -(4)²+6

= -16+6 = -10

5th term = -(5)²+6 = -25+6 = -19

6th term = -(6)²+6 = -36+6 = -30

5,2, -3,-10,-19, -30

optionB

6 0

3 years ago

Graph y<1−3x. .......................... . .

Mkey [24]

Answer:

algobn tu jale

Step-by-step explanation:

yo digo q C es la megor opceon

4 0

3 years ago