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elixir [45]
3 years ago
14

1, 3, 6, 10, 15 is it arithmetic, geometric or neither

Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0

The given sequence is neither arithmetic nor geometric.

Further explanation:

In order to check whether a sequence is geometric or arithmetic we have to find the common ratio and common difference respectively

Common difference is the deifference between cunsecutive terms of a sequence while common ratio is the ratio between two consecutive terms.

Common difference is denoted by d and common ratio is denoted by r

  • If the common difference is same then the given sequence is an arithmetic sequence
  • If the common ratio is same then the given sequence is a geometric sequence

Given

1, 3, 6, 10, 15

Common difference:

Here

a_1=1\\a_2=3\\a_3=6\\a_4=10\\a_5=15\\Common\ Difference=a_2-a_1=3-1=2\\a_3-a_2=6-3=3\\a_4-a_3=10-6=4

As the common difference is not same, the given sequence is not an arithmetic sequence

Common Ratio:

r=\frac{a_2}{a_1}=\frac{3}{1}=3\\\frac{a_3}{a_2}=\frac{6}{3}=2\\\frac{a_4}{a_3}=\frac{10}{6}=1.6

As the common ratio is also not same the sequence is not a geometric sequence.

The given sequence is neither arithmetic nor geometric.

Keywords: Arithmetic sequence, Geometric Sequence

Learn more about sequences at:

  • brainly.com/question/12597153
  • brainly.com/question/12685192

#LearnwithBrainly

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Need help pls<br>thank you in advance ​
ira [324]

Answer:

<h3><u>Mean</u></h3>

<u />

\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}

\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10

\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10

<h3><u>Standard Deviation</u></h3>

\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's.  Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

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