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3 years ago

URGENT. I DO NOT UNDERSTAND: PLEASES LEAVE AN EXPLANATION

Mathematics

1 answer:

Mandarinka [93]3 years ago

7 0

Answer:

Step-by-step explanation:

To find out area of a triangle you must use this formula; Area=1/2bh

In other words, Area equals half times base times height. Since we know that the base is 5/6, fill that in. You can do the rest on your own, (:

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The school is t blocks from Jim's house. The library is twice as far as the school is from Jim's house. How far is the library?

Degger [83]

Answer:

2t blocks

Step-by-step explanation:

We measure these distances from Jim's house.

The school is t blocks from Jim's house. Twice that is 2t blocks. Thus, the library is 2t blocks from Jim's house.

8 0

2 years ago

Find the value of the following expression and round to the nearest integer:

____ [38]

Answer:

This tool can round very big numbers to a very high precision. ... The calculator defaults to rounding to the nearest integer

Step-by-step explanation:

hope i helped

4 0

2 years ago

X/2 = Y/3 = Z/4. prove that :2X-Y+5Z / 3Y-X =3. note :: (/) is for a fraction aka divide. help pls I've been stuck on it for a f

sweet-ann [11.9K]

The given equation

x/2 = y/3 = z/4

can be broken into three separate equations which I'll call equations (A), (B) and (C)

x/2 = y/3 ..... equation (A)
y/3 = z/4 .... equation (B)
x/2 = z/4 .... equation (C)

We'll start off solving for z in equation (C)

x/2 = z/4

4x = 2z ... cross multiply

2z = 4x

z = 4x/2 ... divide both sides by 2

z = 2x

Now let's solve for y in equation (A)

x/2 = y/3

3x = 2y

2y = 3x

y = 3x/2

y = (3/2)x

y = 1.5x

The results of z = 2x and y = 1.5x both have the right hand sides in terms of x. This will allow us to replace the variables y and z with something in terms of x, which means we'll have some overall expression with x only. The idea is that expression should simplify to 3 if we played our cards right.

We won't be using equation (B) at all.

---------------------

The key takeaway from the last section is that

z = 2x
y = 1.5x

Let's plug those items into the expression (2x-y+5z)/(3y-x) to get the following:

(2x-y+5z)/(3y-x)

(2x-y+5(2x))/(3y-x) ..... plug in z = 2x

(2x-y+10x)/(3y-x)

(12x-y)/(3y-x)

(12x-1.5x)/(3(1.5x)-x) .... plug in y = 1.5x

(12x-1.5x)/(4.5x-x)

(10.5x)/(3.5x)

(10.5)/(3.5)

We've shown that plugging z = 2x and y = 1.5x into the expression above simplifies to 3. Therefore, the equation (2x-y+5z)/(3y-x) = 3 is true when x/2 = y/3 = z/4. This concludes the proof.

5 0

2 years ago

Solve 6x+57=2x+315 . A. x=−911 B. x=911 C. x=119 D. x=−119

liubo4ka [24]

Explanation:

Remember: we have to isolate the variable x, so that means we have to get x by itself.

Step 1:

Let’s look at our equation:

$6x+57=2x+315$

Let’s subtract 2x from both sides of the equation, since our goal is to isolate the variable. You could also subtract 6x from both sides, but you would end up with a negative number, and I find it easier to deal with positive numbers.

$6x(-2x)+57=2x(-2x)+315\\4x+57=315$

Step 2:

Now, let’s subtract 57 from both sides of our equation.

$4x+57(-57)=315(-57)\\4x=258$

Step 3:

Since we have to isolate x, let’s divide both sides of the equation by 4.

$4x/4=x\\258/4=64.5$

Our final answer: x = 64.5

None of your options is the correct answer. Notify your teacher, tutor, etc. since there none of the options are correct.

4 0

2 years ago

The probability of rolling two dice at the same time and getting a 4 with either die or the sum of the dice is 6

aleksklad [387]

Answer:

Suppose that the first die we roll comes up as a 1. The other die roll could be a 1, 2, 3, 4, 5, or 6. Now suppose that the first die is a 2. The other die roll again could be a 1, 2, 3, 4, 5, or 6. We have already found 12 potential outcomes, and have yet to exhaust all of the possibilities of the first die. But with a second dice, there will be 24 different possibilities.

Step-by-step explanation:

1 2 3 4 5 6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (<u>6, 4</u>) (6, 5) (6, 6)

4 0

3 years ago