Question

The length of a rectangle is twice its width. if the area of the rectangle is 200 yd2 , find its perimeter.

Answer 1

Width: x
Length: 2x
Area=x(2x)=2x^2
2x^2=200
x^2=100
x=10 or -10(reject as x>0) [width cannot be less than 0, doesnt make sense]
Perimeter
=x+x+2x+2x
=6x
=6(10)
=60 yd

Answer 2

The answer to this question is 60yd