The length of a rectangle is twice its width. if the area of the rectangle is 200 yd2 , find its perimeter.

2 answers:

7 0

Width: x
Length: 2x
Area=x(2x)=2x^2
2x^2=200
x^2=100
x=10 or -10(reject as x>0) [width cannot be less than 0, doesnt make sense]
Perimeter
=x+x+2x+2x
=6x
=6(10)
=60 yd

castortr0y [4]2 years ago

6 0

The answer to this question is 60yd

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The best and most correct answer among the choices provided by your question is the second choice or letter B "20".

The current area is 120(80)=9600 and he want to expand it by 4400 so that the new area will be 9600+4400=14000

14000=(120+x)(80+x)

14000=9600+200x+x^2

x^2+200x-4400=0

x^2-20x+220x-4400=0

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(x+220)(x-20)=0, since x is an increase it must be greater than zero so

x=20ft

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