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mote1985 [20]
3 years ago
5

The length of a rectangle is twice its width. if the area of the rectangle is 200 yd2 , find its perimeter.

Mathematics
2 answers:
Lorico [155]3 years ago
7 0
Width: x
Length: 2x
Area=x(2x)=2x^2
2x^2=200
x^2=100
x=10 or -10(reject as x>0) [width cannot be less than 0, doesnt make sense]
Perimeter
=x+x+2x+2x
=6x
=6(10)
=60 yd
castortr0y [4]3 years ago
6 0
The answer to this question is 60yd

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Suppose you pay back $575 on a $525 loan you had for 75 days. What was your simple annual interest rate? State your result to th
KengaRu [80]

The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.

<h3>What is the interest rate behind a pay back?</h3>

In this situation we assume that the loan does not accumulate interests continuously in time. Hence, the <em>interest</em> rate for paying the loan back 75 days later is:

575 = 525 · (1 + r/100)

50 = 525 · r /100

5000 = 525 · r

r = 9.524

The loan has an <em>interest</em> rate of 9.524 % for 75 days. <em>Simple annual interest</em> rate is determine by rule of three:

r' = 9.524 × 365/75

r' = 46.350

The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.

To learn more on interests: brainly.com/question/26457073

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7 0
2 years ago
015: Rectangle homework
yaroslaw [1]

Answer:

Length: 6 ft

Width: 4 feet

Step-by-step explanation:

Length: L

Width: 2L - 8

2L + 2(2L - 8) = 20

2L + 4L - 16 = 20

6L = 36

L = 36/6

L = 6

W= 2(6)-8 = 4

7 0
3 years ago
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\&#10;\mathsf{8x-32-9x+45=5}\\\\&#10;\mathsf{8x-9x=5+32-45}\\\\&#10;\mathsf{-x=-8}\\\\&#10;\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
100 POINTS IF U GET THIS RIGHT!
Sveta_85 [38]
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\\ \sf\longmapsto m=\dfrac{-3-0}{0+3}=\dfrac{-3}{3}=-1

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\\ \sf\longmapsto y=mx+b

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2 years ago
A cylinder of volume 10pi with a circular bottom and no top is constructed out of two different matierials. the cost of the bott
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