Answer: 225.75g
Explanation:
Molar Mass of Fe(OH)2 = 56 + 2(16 + 1) = 56 + 2(17) = 56 + 34 = 90g/mol
1mole(90g) of Fe(OH)2 contained 6.02x10^23 units.
Therefore, Xg of Fe(OH)2 will contain 1.51x10^24 units
Xg of Fe(OH)2 = (90x1.51x10^24)/6.02x10^23 = 225.75g
<u>Answer:</u> The equilibrium concentration of hydrogen gas is 0.0222 M
<u>Explanation:</u>
We are given:
Initial concentration of hydrogen gas = 0.041 M
Initial concentration of iodine vapor = 0.041 M
Initial concentration of hydrogen iodide = 0.115 M
For the given chemical equation:
Initial: 0.041 0.041 0.115
At eqllm: 0.041-x 0.041-x 0.115+2x
The expression of for above equation follows:
We are given:
Putting values in above equation, we get:
Neglecting the value of x = 0.0816 because, equilibrium concentration cannot be greater than the initial concentration
So, equilibrium concentration of hydrogen gas =
Hence, the equilibrium concentration of hydrogen gas is 0.0222 M