The answer is:
the volume stays the same. it is the pressure that increases
Answer:
0.58 atm
Explanation:
Step 1: Given data
- Total pressure of the gaseous mixture (P): 1.05 atm
- Partial pressure of N₂ (pN₂): 0.35 atm
- Partial pressure of H₂ (pH₂): 0.12 atm
- Partial pressure of CO₂ (pCO₂): ?
Step 2: Calculate the partial pressure of CO₂
The total pressure of the gaseous mixture is equal to the sum of the partial pressures of the individual gases.
P = pN₂ + pO₂ + pCO₂
pCO₂ = P - pN₂ - pO₂
pCO₂ = 1.05 atm - 0.35 atm - 0.12 atm = 0.58 atm
<u>We are given:</u>
The force applied on the poor hamster (F) = 12 N
Acceleration of the poor Hamster (a) = 8 m/s²
<u>Solving for the mass of the Poor Hamster:</u>
From newton's second equation of motion, we know that:
F = ma
<em>replacing the given values</em>
12 = 8 * m
m = 12/8 kg
m = 3/2 kg
The poor Hamster weighs 3/2 kg
Whiteish silver
shiny
ductile
conductor
metal
left
Answer: 
Explanation: For the given reaction:
![Kc=\frac{[Zn^+^2]}{[Ag^+]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BZn%5E%2B%5E2%5D%7D%7B%5BAg%5E%2B%5D%5E2%7D)
Concentrations of the ions are not given so we need to think about another way to calculate Kc.
We can calculate the free energy change using the standard cell potential as:
can be calculated using standard reduction potentials.
Standard reduction potential for zinc is -0.76 V and for silver, it is +0.78 V.
= 
Reduction takes place at anode and oxidation at cathode. As silver is reduced, it is cathode. Zinc is oxidized and so it is anode.
= 0.78 V - (-0.76 V)
= 0.78 V + 0.76 V
= 1.54 V
Value of n is two as two moles of electrons are transferred in the cell reaction F is Faraday constant and its value is 96485 C/mol of electron .
= -297173.8 J
Now we can calculate Kc using the formula:
T = 25+273 = 298 K
R = 
--297173.8 = -(8.314*298)lnKc
297173.8 = 2477.572*lnKc
lnKc = 119.946
