Question

What is true about this relationship?

Answer 1

It is neither an odd nor an even function

Explanation:

I'll assume that the relationship is:

$y=4+x$

In function notation, we can write this as follows:

$f(x)=4+x$

For any even function it is true that:

$f(x)=f(-x)$

For any odd function it is true that;

$f(-x)=-f(x)$

Applying these rules to our function:

RULE FOR EVEN FUNCTION:

$f(x)=4+x \\ \\ f(-x)=4+(-x) \therefore f(-x)=4-x \\ \\ f(x)\neq f(-x)$

It is not an even function!

RULE FOR ODD FUNCTION:

$f(x)=4+x \\ \\ -f(x)=-4-x \\ \\ f(-x)=4+(-x) \therefore f(-x)=4-x \\ \\ f(-x)\neq -f(x)$

It is not an odd function!

__________________________________

So the conclusion is:

It is neither an odd nor an even function

Learn more:

Even function: brainly.com/question/11309886

#LearnWithBrainly