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jek_recluse [69]

3 years ago

13

a party size bag of tortilla chips normally costs 3.80 the market has them on sale for 2.85 what is the percentage of the discou

nt

1 answer:

andreyandreev [35.5K]3 years ago

3 0

It’s 15 percent to be honest I suvj at math and just need points for help I’m sorry

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Please help. 21 points

Eduardwww [97]

Answer:

4/5 ÷3/5

4/5×5/3(any time one is dividing a fraction, the dominator would go up while the numerator would come down).

=4/3

4 0

3 years ago

What is the slope of the line that passes through the points (2,0) and (32,-5)?

grin007 [14]

Answer:

y = -1/6x + 1/3

Step-by-step explanation:

y2 - y1 / x2 - x1

-5 - 0 / 32 - 2

-5 / 30

= -1/6

y = -1/6x + b

0 = -1/6(2) + b

0 = -1/3 + b

1/3 = b

5 0

3 years ago

The price of a liter of milk increased 10% compared with last year . If the new price is $1.21 per liter , what was last years p

Alex Ar [27]

Answer:

$1.1

Step-by-step explanation:

First take if 110% is equals to $1.21 what about 100%

1.21×100=121÷110= $1.1

5 0

3 years ago

4’1” - 1’ 10” whats is

cluponka [151]

Since inches are out of 12 this would be

4 ft - 1 ft = 3 ft

3' 1" - 1 " = 3 '

3 feet is also 2 ft and 12 inches

2' 12" - 9 " = 2' 3"

So the answer is 2 feet and 3 inches

Hope this helps

-GoldenWolfX

7 0

3 years ago

Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

4 0

2 years ago