1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisov135 [29]
3 years ago
11

If it takes 9 1/2 bags of sand to fill 2 1/2 sandboxes how much sand does it take to fill one sandbox

Mathematics
2 answers:
Alchen [17]3 years ago
8 0
We can set up the proportion as follows:
\frac{9.5}{2.5} = \frac{x}{1}
We cross multiply, and get x = 3.8, which is 3 4/5 as a fraction. It takes 3 4/5 bags of sand to fill one sandbox.
---
Hope this helps!
==jding713==
Bumek [7]3 years ago
3 0
Hello.

It takes 3 4/5 bags of sand to fill in one sandbox.

Hope it helps you :)
You might be interested in
The spending limit on John's credit card is given by the function f(t) = 15,000 + 1.57, where x is his monthly income. 1-13) $60
coldgirl [10]
1.
"The spending limit on John’s credit card is given by the function f(x)=15,000+1.5x"

means that if the monthly income of John is $ 5,000 ,he can spend at most

f(5,000)=15,000+1.5*5,000=15,000+ 7,500=22, 500 (dollars)

Or for example

if Johns monthly income is $8,000, then he can spend at most

f(8,000)=15,000+1.5*8,000=15,000+ 12,000=27,000 (dollars)


2.
Now, assume that the maximum amount that John can spend is y.

Then, y=15,000+1.5x

we can express x, the monthly income, in terms of y by isolating x:

y=15,000+1.5x

1.5x = y-15,000
X=y-15,000/1.5

thus, in functional notation, x, the monthly income, is a function , say g, of variable y, the max amount:
X=g(y) y-15000/1.5
since we generally use the letter x for the variable of a function, we write g again as:

G (x) x-15000/1.5
tells us that if the maximum amount that John can spend is 50,000 $, then his monthly income is 23,333 $.

3.

If John's limit is $60,000, his monthly income is
G(600,000)=60,000-15,000/ 1.5=45,000/1.5 =30,000

dollars.


Answer: $ 30,000

Remark: g is called the inverse function of f, since it undoes what f does.

instead of g(x), we could use the notation
5 0
3 years ago
The angle of elevation of the sun is 22∘. A 6ft tall man is standing in the shadow of a 76 ft tall tree so that the tips of thei
Anika [276]

Answer: 173.26 ft = 173 ft

Step-by-step explanation:

h tree: 76 ft

h man: 6 ft

As we can see on the sketch, they form a right triangle, so:

tan 22 = 76/y ⇒ 0.404 = 76/y ⇒ y = 76*0.404 ⇒ y = 188.11 ft

tan 22 = 6/x ⇒ 0.404 = 6/x ⇒ x = 6*0.404 ⇒ x = 14.85 ft

distance between the man and the tree = y - x = 188.11 - 14.85 = 173.26 ft

6 0
3 years ago
I need help on this one <br> No rush but plz hurry I need it NOW‼️‼️
inessss [21]

Answer:

The  same (42 degrees)

Step-by-step explanation:

This is because the angles are congruent or the same.

3 0
3 years ago
Read 2 more answers
Can you guys help me with this question I want to know how to solve this problem ASAP
LekaFEV [45]

Answer:

uh take or add x plus the y then z =5

Step-by-step explanation:

5 0
3 years ago
4x-2y=12. Solve for y
crimeas [40]

Answer:

y = -6 + 2x

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • You can walk 1 3/4 miles in a half hour. what is your average speed?(help meee)
    15·2 answers
  • What is the area of this figure?<br><br> Enter your answer in the box.
    14·1 answer
  • susan was born in 1957 and Valerie was born in 1982.How many years old was susan when valerie was born
    11·2 answers
  • Kirk had 33 points in the game before getting
    5·2 answers
  • Y=-5x – 1<br> how do you find the slope
    5·2 answers
  • A large university accepts 70% of the students who apply. Of the students the university accepts, 30% actually enroll. If 30,000
    5·1 answer
  • Can anyone help me please?
    7·1 answer
  • What is the value of x?
    5·2 answers
  • HELPPP!!! ASAPPP!! PLEASE!! WILL GIVE EXTRA POINTS!!
    6·1 answer
  • Write down the least number of sectors that will cover a
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!