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3 years ago

Write a rule for the nth term of the sequence. Then find a20. Assume the first termis a₁. 86, 79, 72, 65…

Mathematics

1 answer:

hodyreva [135]3 years ago

5 0

Answer:

an = a(n-1) - 7

Step-by-step explanation:

the second term is smaller than the first term 7.

a20 = a19 - 7

a19 = a18 - 7

=> a20 = (a18 - 7) - 7

Then you can accumalate until a1

-> a20 = a1 - 19*7 = 86 - 19*7 = -47

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3 years ago

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An ice cream store sells 28 flavors of ice cream. Determine the number of 4 dip sundaes.

weeeeeb [17]

Answer:

$20,475\ ways$

Step-by-step explanation:

we know that

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

To calculate combinations, we will use the formula

$C(n,r)=\frac{n!}{r!(n-r)!}$

where

n represents the total number of items

r represents the number of items being chosen at a time.

In this problem

$n=28\\r=4$

substitute

$C(28,4)=\frac{28!}{4!(28-4)!}\\\\C(28,4)=\frac{28!}{4!(24)!}$

simplify

$C(28,4)=\frac{(28)(27)(26)(25)(24!)}{4!(24)!}$

$C(28,4)=\frac{(28)(27)(26)(25)}{(4)(3)(2)(1)}$

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3 years ago

What is the density of this object? (A sphere)

igor_vitrenko [27]

9514 1404 393

Answer:

about 0.299 kg/m³

Step-by-step explanation:

Density is the ratio of mass to volume.

ρ = M/V

ρ = (10 kg)/(4/3π(2 m)³) = 15/(16π) kg/m³ ≈ 0.299 kg/m³

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3 years ago

Gil's aunt cut his cake into 32 equal pieces.18 pieces were eaten.what fraction of the cake is left? what is the simplest form o

Eva8 [605]

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3 years ago

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A rectangle has vertices J(3, 3), K(9, 3), L(9, 6), and M(3, 6). Give the coordinates after dilating from the origin by a scale

earnstyle [38]

J'(2,2) , K'(6,2), L'(6,4) and M'(2,4)

Explanation:

Given:

The coordinates of the rectangle are:

J(3, 3), K(9, 3), L(9, 6), and M(3, 6)

The scale factor is 2/3

New coordinates = ?

Multiplying the coordinates by 2/3 to find the vertices of the image

$J(3, 3) = J' (\frac{2}{3} . 3 , \frac{2}{3} . 3) = J' (2,2)\\\\K(9, 3) = K' (\frac{2}{3} . 9 , \frac{2}{3} . 3) = K' (6,2)\\\\L(9, 6) = L' (\frac{2}{3} . 9 , \frac{2}{3} . 6) = L' (6,4)\\\\M(3, 6) = M'(\frac{2}{3} . 3 , \frac{2}{3} . 6) = M' (2,4)$

The vertices of the image are:

J'(2,2) , K'(6,2), L'(6,4) and M'(2,4)

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3 years ago