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Natasha_Volkova [10]
2 years ago
7

Write a rule for the nth term of the sequence. Then find a20. Assume the first termis a₁. 86, 79, 72, 65…

Mathematics
1 answer:
hodyreva [135]2 years ago
5 0

Answer:

an = a(n-1) - 7

Step-by-step explanation:

the second term is smaller than the first term 7.

a20 = a19 - 7

a19 = a18 - 7

=> a20 = (a18 - 7) - 7

Then you can accumalate until a1

-> a20 = a1 - 19*7 = 86 - 19*7 = -47

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Use Ga_thMath(u) (brainly doesn't allow me to type it) To use the app u need to take a pic of the problem and then it will process it and you'll get ur answer ASAP(most of the time). Many questions have been asked before so search it on brainly.

6 0
3 years ago
5.HELP FAST If each person paid an equal amount, who would save the most money? Explain your reasoning using at least two comple
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Answer:

She bought 16

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3 years ago
Help please.........,
Xelga [282]

y-6 = -4(x+1)

y-6 = -4x-4

add 6 to each side

y=-4x+2

A is the correct answer

4 0
3 years ago
Prove the divisibility of the following numbers:
ratelena [41]

Make use of prime factorizations:

16^5+2^{15}=(2^4)^5+2^{15}=2^{20}+2^{15}

Both terms have a common factor of 2^{15}:

16^5+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\cdot33

- - -

The second one is not true! We can write

15^7+5^{13}=(3\cdot5)^7+5^{13}=3^7\cdot5^7+5^{13}

Both terms have a common factor of 5^7:

15^7+5^{13}=5^7\left(3^7+5^6\right)

Since 30=5\cdot6, and 5\mid5^7, we'd still have to show that 5^6(3^7+5^6) is a multiple of 6. This is impossible, because 6=3\cdot2 and there is no multiple of 2 that can be factored out.

4 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-1,7) and is parallel to the line y= -2x-1
Nuetrik [128]

if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, \bf y=\stackrel{slope}{-2}x-1 has a slope of -2.


now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.


\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope =  m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5

3 0
3 years ago
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