This is an equilateral triangle, which is a triangle that has 3 congruent/equal sides and 3 congruent angles.
To find "x", you can set the sides equal to each other because they are suppose to be the same length (you can just do two sides because all of the sides are the same)
[Side AB = Side BC]
4x - 10 = 3x + 2 Subtract 3x on both sides
x - 10 = 2 Add 10 on both sides
x = 12
[proof]
Side AB:
4x - 10 Plug in 12 for x
4(12) - 10 = 48 - 10 = 38
Side BC:
3x + 2 Plug in 12 for x
3(12) + 2 = 36 + 2 = 38
Side AC:
5x - 22 Plug in 12 for x
5(12) - 22 = 60 - 22 = 38
This is also an equilateral triangle (the tick marks show that the sides are the same)
A triangle is 180°. So the three angles add up to 180°.
Since this is an equilateral triangle, all the angles should be the same.
Each angle is 60°
[60° + 60° + 60° = 180° or you could have divided 180 by 3 = 60]
Now that you know each angle is 60°, you can do:
(2x - 4)° = 60°
2x - 4 = 60 Add 4 on both sides
2x = 64 Divide 2 on both sides
x = 32
Answer:
Top left
Step-by-step explanation:
In order for it to be a function, it has to pass the vertical line test. So draw a line down the middle of the graphs. If it passes once, then it is a function, if it passes more than once it is not.
Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so

Answer:
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Step-by-step explanation:
you stupio person you told on me your deab
Answer:
the graph on the right-top
Step-by-step explanation:
Transferring an "x" to the right side in
, we get 
The system of inequalities is

We have y=2x+2 - ascending function with a=2, b=2
b=2 shows that ascending function intersects Y-axis is in y=2 - that situation is only on the right-top and left-down. So, we refuse left-top and right-down.
y=-x-3 - descending function with a=-1, b=-3
y<2x+2 is an area below the ascending function and we see that on the left-
is an area above the descending function
On the left-down we have an area above both functions, so we refuse this picture
Right-top is correct