How do I work this problem out..23÷560

Mathematics

2 answers:

krek1111 [17]3 years ago

7 0

Type in your calculator 560 divided by 23 or you could do long division. The answer is 24.34

attashe74 [19]3 years ago

5 0

Divide 560 by 23, 23 goes into 560 24.347 times.

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! PLEASE HELP QUICKLY !

Travka [436]

Answer:

see below

Step-by-step explanation:

y= 1/2x - 2

To find the x intercept, set y =0 and solve for x

0= 1/2x - 2

Add 2 to each side

2 = 1/2x -2+2

2 = 1/2x

Multiply by 2

2*2 = 1/2x *2

4 =x

The x intercept is 4

3 0

3 years ago

When do we say that the computed solution or root of a quadratic equation is<br>extraneous?<br><br>

scoray [572]

Answer:

raising both sides of the equation to a certain power in order to eliminate radicals may result in the creation of extraneous roots

Step-by-step explanation:

7 0

3 years ago

Use the drop-down menus to complete the proof. Given that w ∥ x and y is a transversal, we know that ∠1 ≅∠5 by the . Therefore,

ololo11 [35]

Answer:

From the graph attached, we know that $\angle 1 \cong \angle 5$ by the corresponding angle theorem, this theorem is about all angles that derive form the intersection of one transversal line with a pair of parallels. Specifically, corresponding angles are those which are placed at the same side of the transversal, one interior to parallels, one exterior to parallels, like $\angle 1$ and $\angle 5$ .

We also know that, by definition of linear pair postulate, $\angle 3$ and $\angle 1$ are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.

They are supplementary by the definition of supplementary angles. This definition states that angles which sum 180° are supplementary, and we found that $\angle 3$ and $\angle 1$ together are 180°, because they are on a straight angle. That is, $m \angle 3 + m \angle 1 = 180\°$

If we substitute $\angle 5$ for $\angle 1$ , we have $m \angle 3 + m \angle 5 = 180\°$ , which means that $\angle 3$ and $\angle 5$ are also supplementary by definition.