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Sliva [168]
4 years ago
7

A seven sides number cube with sides numbered 1,2,3,4,5,6,7 is rolled what is the possibility that an odd number or a seven is r

olled
Mathematics
2 answers:
sergejj [24]4 years ago
6 0

Lets count how many odds there are and how many total there are.

4 odds 7 total. Since we are only calculating for 1 roll 4/7 is the answer.

usually you would add the "or 7 is rolled" but it falls in the odd category so the answer is unchanged.

your answer is 4/7

UNO [17]4 years ago
3 0

You have a 4 out of 7 chance to get an odd number


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find the number of terms in an AP given that its first and last terms are 13 and - 23 respectively and that its common differenc
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Answer:

<u>There are 17 terms in the sequence</u>

Step-by-step explanation:

<u>Arithmetic Sequence </u>

An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:

a_n=a_1+(n-1)r

Where an is the nth term, a1 is the first term, and r is the common difference.

In the problem at hand, we are given the first term a1=13, the last term an=-23, and the common difference r=-2 1/4. Let's solve the equation for n:

\displaystyle n=1+\frac{a_n-a_1}{r}

We need to express r as an improper or proper fraction:

\displaystyle r=-2\frac{1}{4}=-2-\frac{1}{4}=-\frac{9}{4}

Substituting:

\displaystyle n=1+\frac{-23-13}{-\frac{9}{4}}

\displaystyle n=1+\frac{-36}{-\frac{9}{4}}

\displaystyle n=1+36*\frac{4}{9}=17

n=17

There are 17 terms in the sequence

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