The area is 76 ft squared, and the perimeter is 43.1 ft. CORRECT ME IF IM WRONG BECAUSE I WAS SO BAD AT AREA/PERIMETER
Answer:
length of 1 side of A, using the Pyth. Thm. and the dimensions of the other two squares: (side of A)^2 = (10 in)^2 + (24 in)^2. Then:
(side of A)^2 = 100+ 576 in^2 = 676 in^2.
Here I have not bothered to solve for the length of the side of A, since we want the area of square A. But if you do want the side length, find it: sqrt(676) = 26 in. Then the area of A is (26 in)^2 = 676 in^2.
Then the area of square A is (26 in)^2 =
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Step-by-step explanation:
A= player A runs batted in
b= player B runs batted in= a-13
250= a + b
substitute b= a-13 for b
250= a + (a-13)
combine like terms
250= 2a -13
add 13 to both sides
263= 2a
divide both sides by 2
131.5= a
Substitute a= 131.5 into equation
250= a + b
250= 131.5 + b
subtract 131.5 from both sides
118.5= b
Hope this helps! :)
Answer:
Ur final grade will go down if you are looking for answers buddy! :)
Step-by-step explanation:
-6d > 42
d < 42 / (-6)
d < -7