16/4+56-[3+4+1]= WHATS THE ANSWER
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I'm guessing the last value you have down there that got cut off was the one we want. We need to set up the general form of the absolute value equation and then solve it for a: ![y=a[x-h]+k](https://tex.z-dn.net/?f=y%3Da%5Bx-h%5D%2Bk)
. I have no absolute value symbols so I just used brackets. We have a vertex (h, k) of (0, 0) and I picked a point on the graph to use as my x and y coordinates (4, 3). Let's fill in the equation now: ![0=a[0-4]+3](https://tex.z-dn.net/?f=0%3Da%5B0-4%5D%2B3)
. We will subtract 3 from both sides leaving -3 = a[-4]. The absolute value of -4 is 4 so now we have -3 = 4a. Divide by 4 to solve for a. 
. So our equation is ![y=- \frac{3}{4}[x]](https://tex.z-dn.net/?f=y%3D-%20%5Cfrac%7B3%7D%7B4%7D%5Bx%5D%20)
<h3>Look at the picture.</h3>
<em>commutative property</em> a + b = b + a
... (-5 + 1/2 + 5) = ... (-5 + 5 + 1/2)
<em>inverse property of addition</em> a + (-a) = a - a = 0
... (-5 + 5 + 1/2) = ... (0 + 1/2)
<em>identity property of addition</em> a + 0 = 0 + a = a
... (0 + 1/2) = ... 1/2
<em>inverse property of multiplication</em> a/b · b/a = 1
37 · 2 · 1/2 = 37 · 2/1 · 1/2 = 37 · 1
<em>identity property of multiplication</em> a · 1 = 1 · a = a
37 · 1 = 37