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algol [13]
2 years ago
13

Help please please $)

Mathematics
1 answer:
mart [117]2 years ago
6 0
<h3>Look at the picture.</h3>

<em>commutative property</em>  a + b = b + a

... (-5 + 1/2 + 5) = ... (-5 + 5 + 1/2)

<em>inverse property of addition</em> a + (-a) = a - a = 0

... (-5 + 5 + 1/2) = ... (0 + 1/2)

<em>identity property of addition</em> a + 0 = 0 + a = a

... (0 + 1/2) = ... 1/2

<em>inverse property of multiplication</em> a/b · b/a = 1

37 · 2 · 1/2 = 37 · 2/1 · 1/2 = 37 · 1

<em>identity property of multiplication</em> a · 1 = 1 · a = a

37 · 1 = 37

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Karolina [17]

Answer:

x+2 is a factor of f(x)  = 5x^2 + 13x + 6

Step-by-step explanation:

To check: If (x+2) is a a factor of the polynomial f(x)  = 5x^2 + 13x + 6

We need to check if x  = -2 is the FACTOR of the given polynomial.

⇒ To show:  f (-2)  =  0

Now

f(-2)  = 5(-2)^2 + 13(-2) + 6\\=5(4) -26 + 6\\= 20 + 6 - 26\\= 26 - 26  = 0\\\implies f(-2) = 0

Since, f(-2) = 0

⇒  -2 is the ROOT of the Polynomial f(x).

⇒(x +2) is the factor of the given polynomial.

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NOTES:

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Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

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= 1 + 9

= 10

***************************************************************************************

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5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

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