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pashok25 [27]
4 years ago
9

Let h(x) = e^(kx) + f(x),

Mathematics
1 answer:
Anestetic [448]4 years ago
3 0
\bf h(x)=e^{kx}+f(x)\implies \cfrac{dh}{dx}=ke^{kx}+f'(x)
\\\\\\
\begin{cases}
x=0\\
f'(0)=-8
\end{cases} 
h'(0)=ke^{k(0)}+(-8)\implies h'(0)=k-8
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Answer:

the probability the rock has raritanium is 0.9670

Step-by-step explanation:

These events have been defined as

Z: sample has raritanium

Y: the reading from detector is positive

Z': sample has no raritanium

Y': Reading from detector is negative

P(z) = 0.13

P(y'/z) = 0.02

P(y/z')= 0.005

We need to find p(z/y)

= p(z/y) = p(z ∩ y)/p(y)

= P(z) - p(z∩y)/0.13 = 0.02

Remember the value of p(z) = 0.13

So when we cross multiply we get

0.13 - p(z ∩ y) = 0.02 x 0.13

0.13 - p(z ∩ y) = 0.0026

-p(z ∩ y) = 0.0026 - 0.13

Such that

p(z ∩ y) = 0.1274

P(y/z')= 0.005

P(z∩y') = 0.005

Since p(z) = 0.13

P(z') = 1-0.13

P(y) - p(z∩y)/0.87 = 0.005

We cross multiply

P(y) - 0.1274 = 0.005x0.87

P(y) = 0.1274+0.00435

P(y) = 0.13175

We have 0.1274/0.13175

= 0.9670

So we conclude that probability rock has raritanium is 0.9670

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3 years ago
Write an equation of the line below.
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Y=mx+b is the equasion of a line.
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