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3 years ago

Let h(x) = e^(kx) + f(x),

1 answer:

3 0

$\bf h(x)=e^{kx}+f(x)\implies \cfrac{dh}{dx}=ke^{kx}+f'(x)
\\\\\\
\begin{cases}
x=0\\
f'(0)=-8
\end{cases} 
h'(0)=ke^{k(0)}+(-8)\implies h'(0)=k-8$

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Answer the following questions 0.2 is what percent of 1 3/5 ? plzzz help me

liraira [26]

Answer:

1 3/5 = 8/5

.2=2/100

Step-by-step explanation:

make an equality:

x/(8/5)=2/100

it kinds looks weird on here but write it out on paper

then cross multiply:

100x=(2)(8/5)

100x=16/5

now divide each side by 100:

x=4/125

same for the second one:

make an equality:

x/2=2/100

cross multiply:

100x=(2)(2)

100x=4

x=1/25

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3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 mill

ki77a [65]

Based in your question where as the oil is pumped continuously from the well at a rate proportional to the amount of the oil left in the well. so the answer of the following questions are:
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2 years ago

a homework assignment included 40 multiple choice questions Sabrina completed 65% of her assignment in David completed 4/5 of hi

bazaltina [42]

Answer:

6 or -6

Step-by-step explanation:

65% of 40=26
4/5 of 40=32
32-26=6
(or if you start with 26)
26-32=-6

7 0

2 years ago

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Is it okay to eat 8 day used by bread that been left in the refrigherater

FrozenT [24]

Bread is usually fine to eat if you don't see any mold.

Once refrigerated, it will retain its freshness for three to four days before becoming stale. If you want to extend its shelf life, packaged bread will stay fresh for at least three months in the freezer. If you do see mold, however, throw the bread out.

8 0

2 years ago

A coin is tossed 5 times. Find the probability that all are heads. Find the probability that at most 2 are heads.

fenix001 [56]

Answer:

1/32

15/32

Step-by-step explanation:

For a fair sided coin,

Probability of heads, P(H) = 1/2

Probability of tails P(T) = 1/2

For a coin tossed 5 times,

P( All heads)

= P(HHHHH),

= P (H) x P(H) x P(H) x P(H) x P(H)

= (1/2) x (1/2) x (1/2) x (1/2) x (1/2)

= 1/32 (Ans)

For part B, it is easier to just list the possible outcomes for

"at most 2 heads" aka "could be 1 head" or "could be 2 heads"

"One Head" Outcomes:

P(HTTTT), P(THTTT) P(TTHTT), P(TTTHT), P(TTTTH)

"2 Heads" Outcomes:

P(HHTTT), P(HTHTT), P(HTTHT), P(HTTTH), P(THHTT), P(THTHT), P(THTTH), P(TTHHT), P(TTHTH), P(TTTHH)

If we count all the possible outcomes, we get 15 possible outcomes representing "at most 2 heads)

we know that each outcome has a probability of 1/32

hence 15 outcomes for "at most 2 heads" have a probability of

(1/32) x 15 = 15/32

8 0

3 years ago

Read 2 more answers