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3 years ago

10

Y - 1/3 is greater than 1/8

1 answer:

velikii [3]3 years ago

4 0

If this is a true or false question, than this is true.

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Use trigonometry to find the value of x. Round your answer to the nearest whole degree

Paladinen [302]

70% degree I hope that’s the right answer

8 0

3 years ago

How?!? I don't know what to do

Goshia [24]

This is easy, if adding the first number to the second number you get 70.2 then if you want to find the middle number you will have to subtract 32.34 from 70.2 to get 37.86, now add that and 32.34 to check if it gives you 70.2.... When you add them you indeed get 70.2 so your work is correct meaning your middle number is 37.86

Hope this helped

3 0

3 years ago

Someone please help ASAP will give brainliest

Nimfa-mama [501]

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

You need to find "m" and "b".

If you look at the graph, when x = 0, y is 1, so the y-intercept is 1.

y = mx + 1

To find "m", you can use the slope formula and find two points on the graph and plug it in, or you can use this:

$slope=\frac{rise}{run}$

Rise is the number of units you go up(+) or down(-)

Run is the number of units you go to the right.

If you look at the graph, from each point you go up 1 unit, and to the right 1 unit. So your slope is $\frac{1}{1}$ or 1

y = 1x + 1

y = x + 1

4 0

3 years ago

Read 2 more answers

Math work pls help :)

PilotLPTM [1.2K]

Answer:

b. side angle side. hope this helps

8 0

2 years ago

What is an equation of the line that passes through the points (-6, -2) and

den301095 [7]

Answer:

The equation of line is: $\mathbf{4x-3y=-18}$

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?

The equation of line in slope-intercept form is: $y=mx+b$

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=-6,y_1=-2, x_2=-3, y_2=2$

Putting values and finding slope

$Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}$

So, we get slope: $m=\frac{4}{3}$

Finding y-intercept

Using point (-6,-2) and slope $m=\frac{4}{3}$ we can find y-intercept

$y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6$

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope $m=\frac{4}{3}$ and y-intercept b = 6 is

$y=mx+b\\y=\frac{4}{3}x+6$

Now transforming in fully reduced form:

$y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18$

So, the equation of line is: $\mathbf{4x-3y=-18}$

6 0

2 years ago