Sorry dont know, any thing else you need help with?
Macro needs 90 megabytes of storage to store the whole video.
Step-by-step explanation:
Video downloaded = 80%
Data storage used = 72 MB
Let, x be the total data storage required for storing the whole video.
Therefore,
80% of x = 72
![\frac{80}{100}*x=72\\0.8x=72\\](https://tex.z-dn.net/?f=%5Cfrac%7B80%7D%7B100%7D%2Ax%3D72%5C%5C0.8x%3D72%5C%5C)
Dividing both sides by 0.8
![\frac{0.8x}{0.8}=\frac{72}{0.8}\\x=90\ MB](https://tex.z-dn.net/?f=%5Cfrac%7B0.8x%7D%7B0.8%7D%3D%5Cfrac%7B72%7D%7B0.8%7D%5C%5Cx%3D90%5C%20MB)
Macro needs 90 megabytes of storage to store the whole video.
Keywords: percentage, division
Learn more about division at:
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Area of isosceles triangle is 63.98 square units.
<u>Solution:</u>
Note: Refer the image attached below
Given that leg of an isosceles triangle is 16; Measured of one of the angle is 150; Need to determine area of triangle.
Consider the figure ABC is required isosceles triangle
From given information,
AC = CB = 16 and ![\angle \mathrm{ACB}=150^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20%5Cmathrm%7BACB%7D%3D150%5E%7B%5Ccirc%7D)
So we have two sides and angle between them. Let us use law of cosine
On applying law of cosine on triangle ABC we get,
![\begin{array}{l}{\mathrm{AB}^{2}=\mathrm{AC}^{2}+\mathrm{CB}^{2}-2 \times \mathrm{AC} \times \mathrm{CB} \cos \mathrm{C}} \\\\ {=>\mathrm{AB}^{2}=16^{2}+16^{2}-2 \times 16 \times 16 \cos 150} \\\\ {\Rightarrow \mathrm{AB}^{2}=16^{2}+16^{2}+443.4} \\\\ {\Rightarrow \mathrm{AB}^{2}=955.4} \\\\ {\Rightarrow \mathrm{AB}=30.91}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Cmathrm%7BAB%7D%5E%7B2%7D%3D%5Cmathrm%7BAC%7D%5E%7B2%7D%2B%5Cmathrm%7BCB%7D%5E%7B2%7D-2%20%5Ctimes%20%5Cmathrm%7BAC%7D%20%5Ctimes%20%5Cmathrm%7BCB%7D%20%5Ccos%20%5Cmathrm%7BC%7D%7D%20%5C%5C%5C%5C%20%7B%3D%3E%5Cmathrm%7BAB%7D%5E%7B2%7D%3D16%5E%7B2%7D%2B16%5E%7B2%7D-2%20%5Ctimes%2016%20%5Ctimes%2016%20%5Ccos%20150%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20%5Cmathrm%7BAB%7D%5E%7B2%7D%3D16%5E%7B2%7D%2B16%5E%7B2%7D%2B443.4%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20%5Cmathrm%7BAB%7D%5E%7B2%7D%3D955.4%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20%5Cmathrm%7BAB%7D%3D30.91%7D%5Cend%7Barray%7D)
Now we are having three sides of triangle,
AB = 30.91; BC = 16 and CA = 16
As three sides are given, we can apply heron’s formula to determine area of triangle ABC. According to herons formula,
![\begin{array}{l}{\text { Area of Triangle }=\sqrt{s(s-a)(s-b)(s-c)}} \\\\ {\text { Where } s=\frac{a+b+c}{2}}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7B%20Area%20of%20Triangle%20%7D%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20Where%20%7D%20s%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%7D%5Cend%7Barray%7D)
In our case a = AB = 30.91; b = BC = 16; c = CA = 16
![\begin{array}{l}{\text { So } s=\frac{A B+B C+C A}{2}=\frac{30.91+16+16}{2}=31.455} \\\\ {\text { Area of Triangle } A B C=\sqrt{31.455(31.455-30.91)(31.455-16)(31.455-16)}} \\\\ {\Rightarrow \text { Area of Triangle } A B C=\sqrt{31.455 \times 0.545 \times 15.455 \times 15.455}=\sqrt{4094.72}=63.98}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7B%20So%20%7D%20s%3D%5Cfrac%7BA%20B%2BB%20C%2BC%20A%7D%7B2%7D%3D%5Cfrac%7B30.91%2B16%2B16%7D%7B2%7D%3D31.455%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20Area%20of%20Triangle%20%7D%20A%20B%20C%3D%5Csqrt%7B31.455%2831.455-30.91%29%2831.455-16%29%2831.455-16%29%7D%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20%5Ctext%20%7B%20Area%20of%20Triangle%20%7D%20A%20B%20C%3D%5Csqrt%7B31.455%20%5Ctimes%200.545%20%5Ctimes%2015.455%20%5Ctimes%2015.455%7D%3D%5Csqrt%7B4094.72%7D%3D63.98%7D%5Cend%7Barray%7D)
The ratio of blue paint to yellow paint is 2 : 3.
The total number of blue paint he used on the first and second day is 10.
The number of yellow paint he used on the first and second day is 15.
On the third day, the highest number of can of blue paint he can use is 2
On the third day, the highest number of can of yellow paint he can use is 3.
<h3>What is the highest number of blue and yellow paint he can use?</h3>
The ratio of blue paint to yellow paint can be determined by determining the simplest form of the paints used: 4 : 6 = 2: 3
Total blue paint cans used on the first and second day = 4 + 6 = 10
Blue paint cans remaining = 14 - 10 = 4
Total yellow paint cans used on the first and second day = 6 + 9 = 15 cans
Yellow paint cans remaining = 20 - 15 = 5 cans
Please find attached the questions. To learn more about ratios, please check: brainly.com/question/19711539
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