6x^3y^9/36x^3y^-2 The x^3 values cancel each other out leaving the 1/6
(1/6)y^9/(y^-2) the y^-2 causes the y^9 to turn into y^11 (9+2=11)
(1/6)y^11/1 the 1/6 is multiplied by y^11
y^11/6
Can you be more specific on the problem
Answer:
A
Step-by-step explanation:
RT=12
TU=5
RU=12+5=17
RS=17+7=24
SU=√(RS²-RU²)=√(24²-17²)=√(24-17)(24+17)=√(7×41)=√287
area=1/2×12×√287=6×√287≈101.6 unit²
Answer:
-8y+12
Step-by-step explanation:
4(-2y +3)
you can distribute the 4
4 • -2y + 4 • 3
= -8y +12
because they are not like terms, you cannot do anything further.
