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stepan [7]
3 years ago
10

Eric and Shiloh each have a savings account. The ratio of Eric’s account balance to Shiloh’s account balance is 4:3. Together th

ey have a total of $140 in their accounts. Use the tape diagram below to help you determine the balance of Eric’s account.
Mathematics
2 answers:
Ronch [10]3 years ago
5 0

Answer:

The answer will get is $80/$60


Step-by-step explanation:


Mila [183]3 years ago
4 0

Answer:

The answer is $80 / $60


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Two pound bags of candy are being used to fill containers that hold 1 1/2 pounds each. How many containers can be filled by each
melamori03 [73]

Answer:

4 Containers Can Be Filled By Each Two Pound Bag Of Candy .

Step-by-step explanation:

GIven   Two Pound Bag Of Candy Used To Fill Container That hold 1\frac{1}{2} Pound Each .

Now There are 4 Container of Capacity 1\frac{1}{2}  Pound Needed To fill Exactly 3 two Pound Bags .

Thus 4 container have Total capacity Of 6 Pound . Which Is Easily Filled By The 3 two Pound Bags . ( Without Any Loss )

3 0
3 years ago
a train travels 120 miles in 1 1/2 hours. At this rate how many miles will the train travel in 6 hours
Morgarella [4.7K]

Answer:

480 miles

Step-by-step explanation:

120/1.5=80

80*6=480

6 0
3 years ago
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Last year she sold 108 cars this year her goal is to sell 250% as many cars how many cars must she sell to reach her goal
ivann1987 [24]

Answer:

270

Step-by-step explanation:

8 0
3 years ago
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Someone please help??
irga5000 [103]

Answer:

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Step-by-step explanation:

8 0
2 years ago
A closet contains n pairs of shoes. If 2r shoes are chosen at random, (where 2r < n), what is the probability that there will
Pie
We are choosing 2
2
r
shoes. How many ways are there to avoid a pair? The pairs represented in our sample can be chosen in (2)
(
n
2
r
)
ways. From each chosen pair, we can choose the left shoe or the right shoe. There are 22
2
2
r
ways to do this. So of the (22)
(
2
n
2
r
)
equally likely ways to choose 2
2
r
shoes, (2)22
(
n
2
r
)
2
2
r
are "favourable."

Another way: A perhaps more natural way to attack the problem is to imagine choosing the shoes one at a time. The probability that the second shoe chosen does not match the first is 2−22−1
2
n
−
2
2
n
−
1
. Given that this has happened, the probability the next shoe does not match either of the first two is 2−42−2
2
n
−
4
2
n
−
2
. Given that there is no match so far, the probability the next shoe does not match any of the first three is 2−62−3
2
n
−
6
2
n
−
3
. Continue. We get a product, which looks a little nicer if we start it with the term 22
2
n
2
n
. So an answer is
22⋅2−22−1⋅2−42−2⋅2−62−3⋯2−4+22−2+1.
2
n
2
n
⋅
2
n
−
2
2
n
−
1
⋅
2
n
−
4
2
n
−
2
⋅
2
n
−
6
2
n
−
3
⋯
2
n
−
4
r
+
2
2
n
−
2
r
+
1
.
This can be expressed more compactly in various ways.
4 0
3 years ago
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