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Sveta_85 [38]
3 years ago
6

Look at the rational expression below. x^2-4/2-x Which value of x makes the expression undefined?

Mathematics
2 answers:
Andreas93 [3]3 years ago
4 0
The answer would 2, since you cannot divide anything by 0 as it would be undefined. 2 is the only number that gives you this option 
Furkat [3]3 years ago
3 0

Answer:

given rational function is undefined for x = 2

Step-by-step explanation:

The given rational function is

\frac{x^2-4}{2-x}

The rational function is undefined if the denominator is zero.

Hence, the given rational function is undefined if

2-x=0

Solve the equation for x

x=2

Therefore, the given rational function is undefined for x = 2

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Zx = 34°; Zy = 62°; Zz =​
Bumek [7]

Answer:

Zz=84 degrees

Step-by-step explanation:

The angles of a triangle add up to 180 degrees, so 34+62+Zz=180. Subtract the 34 and 62 from the 180 to get 84. This is Zz. :)

5 0
3 years ago
F(x)=-2x^2+x-5 find f(5)
julsineya [31]

f(5) = -50

Hope it helps you...

6 0
3 years ago
3/1/2+1/5/6÷1/3/5 <br>hello good afternoon can u please solve this question​
Likurg_2 [28]

Answer:

1/2

Step-by-step explanation:

See the steps below:)

7 0
3 years ago
Elena said the equation 9x+15=3x+15 has no solutions because 9x is greater than 3x. Do you agree with Elena? Explain your reason
baherus [9]

Answer:

Disagree

Step-by-step explanation:

You can solve this problem by doing as follows:

9x+15=3x+15

-3x        -3x

=

6x+15=15

-15        -15

=

6x=0

Although x=0, x=0 is still a solution to the problem.

8 0
4 years ago
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Helpppppppppppppppppppppp..... .......<br><br><br>​
morpeh [17]

Answer:

{ \sf{( \sec \theta -  \csc \theta)(1 +  \tan \theta +  \cot \theta) }} \\  = { \sf{( \sec \theta +  \tan \theta \sec \theta +  \cot  \theta \sec  \theta) - ( \csc  \theta -   \csc \theta \tan  \theta -  \csc \theta \cot  \theta)}} \\  = { \sf{( \sec \theta +  \sec \theta \tan  \theta +  \csc  \theta) - (  \csc  \theta -  \sec \theta -  \csc  \theta \cot   \theta)}} \\  = { \sf{ \sec  \theta \tan  \theta +  \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}

3 0
3 years ago
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