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3 years ago

Solve the following for the variable: 15x−3=2

Mathematics

2 answers:

JulsSmile [24]3 years ago

8 0

Answer:

15x3= - 3 =2

Step-by-step explanation:

vekshin13 years ago

6 0

Hello!!!

↓↓

$15x-3+3=2+3\\\\12x=5\\\\\frac{15x}{15}\frac{5}{15} \\\\x=\frac{1}{3}$

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What is the answer?

Bad White [126]

Answer:

k=3

Step-by-step explanation:

+ we note f(p)= $p^{4}+p^{2} +p -k$

+ Because of "p-1 is a factor of f(p)", that means f(p)= (p-1)* g(p)

Then we have f(1)= (1-1)*g(1)= 0* g(1)= 0

+ We replace p=1 in f(p) and we have:

f(1)=0

that means: $1^{4}+1^{2} + 1 - k=0$

then 1+1+1-k = 0, 3-k=0 or k=3

Hope that useful for you.

8 0

3 years ago

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

3 years ago

Can someone help me please

Charra [1.4K]

Answer:

of coure. this is alternative B.

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3 years ago

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frez [133]

31 is the answer eeeee

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3 years ago

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Write as an expression: twice the product of the cube of a and the square of b

Tju [1.3M]

Answer:

the square root of 2(x^3 * x^2)

Step-by-step explanation:

twice means 2 and product means either division or multiplication (multiplication in this scenario because twice means multiply). cubed means to the third power

note i don't know how to put a square root sign so i wrote it out

hope i helped

8 0

3 years ago

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