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natka813 [3]
3 years ago
10

Russian psychologist Lev Vygotsky was particularly interested in how the _____ affects a child's cognitive development.

Advanced Placement (AP)
1 answer:
-Dominant- [34]3 years ago
6 0
Social interaction and environment
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Margarita [4]
The answer is 1 because others are biased and it seems like the best answer
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3 years ago
which are the advantages of the new road near tthe school and which is the disadvantages of the new road near the school
pickupchik [31]

it makes it easier to go there but when it is the end of the day it can cause a lot accidents when students are getting to school

4 0
4 years ago
. तलको अनुच्छेद पढी सोधिएका प्रश्नको उत्तर लेख्नुहोस् । हिमालमा बाहै महिना हिउँ जमिरहने हुनाले वातावरण निकै चिसो हुन्छ । चिसो वा
Mariulka [41]

Answer:

क) हिमाली भेगको वातावरण किन चिसो हुन्छ ?

=हिमालमा बाहै महिना हिउँ जमिरहने हुनाले हिमाली भेगको वातावरण निकै चिसो हुन्छ ।

ख) हिमाली भेगमा किन मान्छेको वसोवास कम हुन्छ ?

=हिमाली भेगमा चिसो वातावरण भएकाले हिमालमा मान्छेको बसोवास अत्यन्तै कम हुन्छ ।

ग) नेपाला आठ हजार भन्दा माथिका कति हिमाल नेपालमा पर्दछ ?

= नेपालमाआठ हजार भन्दा बढीका करीव ८ हिमाल नेपालमा पर्दछ

घ) नेपालमा वर्षेनी विदेशी पर्यटकहरू किन आउने गर्दछन् ?

=नेपालमा हिमाल चढ्न र हेर्न वर्षेनी विदेशी पर्यटकहरू नेपाल आउने गर्छन् ।

ङ) 'जडीबुटी' र 'वर्षेनी' शब्दको अर्थ लेख्नुहोस् ।

जडीबुटी=औषधी

वर्षेनी=बर्षे पछि

8 0
3 years ago
How does mercantilism shape Britain's view of the american colonies
aleksandrvk [35]

Answer:

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ee

Step-by-step explanation:

we

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ee

Step-by-step explanation:

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Explanation:

4 0
3 years ago
A plane flying at a certain altitude is observed from two points that are 3 miles apart. The angles of elevation made by the two
kobusy [5.1K]

Answer:

8.0 mi  

Explanation:

Let's call your triangle ABC as in the diagram. We can use the SAS property of triangles and the Law of Sines.

1. Determine m∠B

m∠ B + 72° = 180°

         m∠B = 108°

2. Determine b

By the Law of Sines,

b/sinB = c/sinC

       b = c(sinB/sinC)

          = 3 × (sin108°/sin17°)

          = 3 × 0.951/0.292

          = 9.76 mi

3. Calculate the area of ∆ABC

Area = ½ bc sinA = ½ × 9.76 × 3sin55° = ½ × 9.76 × 3 × 0.819 = 12.0 mi²

4. Calculate h

Area = ½ × base × height

12.0 mi² = ½ × 3 mi × h

h = 2 × 12.0 mi/3= 8.0 mi  

The altitude of the plane is 8.0 mi.

4 0
4 years ago
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