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bulgar [2K]
3 years ago
12

Find two numbers if their sum is 6.1 and their difference is 1.6

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
5 0
A+b=6.1 ---(1)
a-b=1.6 ---(2)

(1)+(2); 2a=7.7
then a=3.85
so b=a-1.6 = 3.85-1.6 = 2.25

so that the two numbers are 2.25 and 3.85
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<span>Clarke borrows $16000 to buy a car he pays simple interest at an annual rate of 6% over a period of 3.5 years how much does he pay all together?
Let’s calculate
=> 16 000 dollars is the amount he borrowed
=> 6% is the annual interest
=> 3.5 years us the total years that he will be paying it.
Solutions:
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A table shaped like a solid cube needs to painted. All six faces of the table must be painted. The edge length of the table is 1
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C. 8.64m^2 because one face of the cube has a surface area of 1.44m^2 (1.2*1.2) and a cube has 6 sides (6*1.44).
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Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste
lisabon 2012 [21]

Answer:

(a) The value of <em>x</em> is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.

Step-by-step explanation:

Denote the events as follows:

<em>R</em> = reported case of rabies is a raccoon

<em>F</em> = reported case of rabies is a fox

<em>B</em> = reported case of rabies is a bat

<em>O</em> = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = <em>x</em>.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, \sum P(X)=1

Compute the value of <em>x</em> as follows:

\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30

Thus, the value of <em>x</em> is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

P(A^{c})=1-P(A)

Compute the probability that a reported case of rabies is not a raccoon as follows:

P(R^{c})=1-P(R)\\=1-0.55\\=0.45

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

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Answer:

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