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ollegr [7]
3 years ago
12

Walter buys a bus pass for $$30.00 every time he rides the bus, money is deducted from the value of the pass. he rode the bus 12

times and $24.00 was deducted from the value of the pass. how much money does each bus ride cost
Mathematics
2 answers:
grandymaker [24]3 years ago
3 0
Each bus ride costs $2
Len [333]3 years ago
3 0
Each bus ride costs $2
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Is 272 oz greater than 20 lb
Karolina [17]
We know that 1 lb = 16 oz
So lets convert the 20 lb to oz and then compare the two quantities in consistent units.
If 1 lb = 16 oz then 20 lb are equal to 20*16 oz, that is
20 lb = 20*16 oz = 320 oz
therefore,
320 oz are greater than 272 oz, or,
20 lb are greater that 272 oz
3 0
3 years ago
PLEASE help me with these 2 questions!!
dimaraw [331]

You do not want the "b" since two of the equations start off at 0 kites.

x=kites purchased

Kities : y=8x

Windy Kites: y=20x

From there, all you need to do is plug in the kite purchased number replacing x.

4 0
3 years ago
Ana is having dinner at a restaurant. Her bill before adding sales tax and tips is $23.20. The restaurant add the sales tax of 7
Aneli [31]
Start by finding 7% of the $23.20:

\frac{7}{100} *23.20=1.624

Now add this to $23.20:

23.20+1.624=24.824

Now, let's find 18% of this new total with tax to find the tip amount:

\frac{18}{100} *24.824=4.46832

This is the tip amount. And finally, let's add this to the 24.824:

24.824+4.46832=29.29232

Not sure if you were given any instructions about rounding, but Ana's cost will be around $29.29.

Hope this helps.
4 0
3 years ago
Copy the problems on to your paper. Use your notes as reference.
____ [38]

Answer:

1. x⁴³/³⁵

2. 1/x⁶

3. x⁴/2

Step-by-step explanation:

1. ⁷√x³. ⁵√x⁴

The above expression can be simplified as follow:

Recall:

ᵐ√aⁿ = aⁿ/ᵐ

⁷√x³ × ⁵√x⁴ = x³/⁷ × x⁴/⁵

Recall:

aⁿ × aᵐ = aⁿ⁺ᵐ

x³/⁷ × x⁴/⁵ = x⁽³/⁷ ⁺ ⁴/⁵⁾ = x⁴³/³⁵

Therefore,

⁷√x³. ⁵√x⁴ = x⁴³/³⁵

2. x¯³ / x⁵x¯²

The above expression can be simplified as follow:

Recall:

aⁿ × aᵐ = aⁿ⁺ᵐ

x⁵x¯² = x⁵ ⁺ ⁽¯²⁾ = x⁵ ¯ ² = x³

Thus,

x¯³ / x⁵x¯² = x¯³ / x³

Recall:

aⁿ / aᵐ = aⁿ ¯ ᵐ

x¯³ / x³ = x¯³ ¯ ³ = x¯⁶

Recall

a¯ⁿ = 1/aⁿ

x¯⁶ = 1/x⁶

Therefore,

x¯³ / x⁵x¯² = 1/x⁶

3. 5(x⁴)³ / 10x⁸

The above expression can be simplified as follow:

Recall:

(aⁿ)ᵐ = aⁿ×ᵐ

5(x⁴)³ / 10x⁸ = 5x¹² / 10x⁸

Recall:

aⁿ / aᵐ = aⁿ ¯ ᵐ

5x¹² / 10x⁸ = (5/10)x¹² ¯ ⁸ = 1/2 x⁴ = x⁴/2

Therefore,

5(x⁴)³ / 10x⁸ = x⁴/2

6 0
3 years ago
Find rules for quadratic functions with graphs meeting these conditions.
Elena L [17]
1.) (x - 4)(x + 1) = 0
x^2 + x - 4x - 4 = 0
y = x^2 - 3x - 4

2.) (x - 2)(x - 6) = 0
x^2 - 6x - 2x + 12 = 0
x^2 - 8x + 12 = 0
since the function has a maximum point the leading coefficient is negative.
Therefore, required equation is y = -3x^2 + 24x - 36

3.) a(x + 3)^2 = ax^2 + 6ax + 9a
since the y intercept is at y = 18 => 9a = 18 => a = 2
Therefore, required function is y = 2x^2 + 12x + 18
8 0
4 years ago
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