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3 years ago

Is 8/6 greater than or less than 11/12

2 answers:

8 0

$\frac{8}{6}\ \ \ \ and\ \ \ \ \frac{11}{12}\ \ \ \ \ | make\ a\ common\ denominator\ 12\\\\
\frac{16}{12}\ \ \ and\ \ \ \ \frac{11}{12}\\\\
Now\ it\ is\ visible\ that\ \frac{16}{12} \ >\ \frac{11}{12}\ so\ \frac{8}{6} \ >\ \frac{11}{12}\ 
$

Nezavi [6.7K]3 years ago

7 0

Greater because 8/6 is equal to a Whole number well more than a Whole number and 11/12 is less than aWhole number

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If guy walks from his house to school and back,how far does he walk?

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A middle school has 600 students and 34% of them are in the 8th grade. One-fourth of 8th graders walk to school. How many 8th gr

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The ardered.pairs.(0, 1), (3, 10) and (4, n) are solutions of the same linear equation. Find n.

Fittoniya [83]

Answer:

n = 13.

Step-by-step explanation:

Slope of the line = (10-1)/3-0) = 3

So the equation of the line is:

y - 1 = 3(x - 0)

y = 3x + 1

When x = 4 y = n, so:

n = 3(4) + 1 = 13.

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2 years ago

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is

insens350 [35]

Answer:

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

Step-by-step explanation:

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is less than 0.16.

This means that the null hypothesis is:

$H_{0}: p \geq 0.16$

Testing this hypothesis, means that the alternate hypothesis is:

$H_{a}: p > 0.16$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.16 is tested at the null hypothesis:

This means that $\mu = 0.16, \sigma = \sqrt{0.16*0.84}$

In a sample of 200 graduates, 24 students have a GPA of 3.00 or below.

This means that $n = 200, X = \frac{24}{200} = 0.12$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.12 - 0.16}{\frac{\sqrt{0.16*0.84}}{\sqrt{200}}}$

$z = -1.54$

Pvalue:

The pvalue is the probability of finding a sample mean above 0.12, which is 1 subtracted by the pvalue of z = -1.54.

Looking at the z-table, z = -1.54 has a pvalue of 0.0618

1 - 0.0618 = 0.9382

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

6 0

3 years ago

Please answer fast and give expaination I will give brainliest

loris [4]

Answer:

Agree.

Step-by-step explanation:

1. (5^r)^t can be represented simply as 5^rt.

2. when r as negative integer, t as positive integer, rt is always a negative integer

3. when ever the indices rt is negative, the number 5^rt will be less than 1, thus cannot be a whole number for sure.

5 0

2 years ago