Step-by-step explanation:
then poured into another container with a rectangular base of length 27 cm and width 11 cm. Calculate the depth (height) of the water in the rectangular container
Answer:
$20.05 is Cassie's change
Step-by-step explanation:
60.00-29.95=30.05
30.05-10=20.05
Y - Y2 = M(x-x2)
M = (-3/2) or (3/-2)
Y -(-3) = (-3/2) (X-2)
Y + 3 = (-3/2)(X-2)
Answer:

Step-by-step explanation:
We have
square with sides <em>s = 3cm</em>
four triangles with base <em>b = 3cm</em> and height <em>h = 9cm</em>.
The formula of an area of a square:

The formula of an area of a triangle:

Substitute:

The Surface Area:

<h3>
Answer: 40</h3>
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Explanation:
JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.
See the diagram below.
The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)
We know that JN = 60
Let x = JQ and y = QN
The ratio of x to y is x/y and this is 2/1
x/y = 2/1
1*x = y*2
x = 2y
Now use the segment addition postulate
JQ + QN = JN
x + y = 60
2y + y = 60
3y = 60
y = 60/3
y = 20
QN = 20
JQ = 2*y = 2*QN = 2*20 = 40
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We have
JQ = 40 and QN = 20
We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.