Answer:
2(d - 3) is the equation. You cannot solve for d. You can only simplify it
Answer:
B
Step-by-step explanation:
The equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
h= 9, k = -7
r = 2, so r^2 = 4.
We now know that the equation must equal 4, so we can rule out answers A and C.
Plug in the values for h and k to get
(x-9)^2 + (y+7)^2 = 4
Choice B is correct!
1
-
2
Put it like that and there’s your constant
we are given
![\frac{\sqrt[3]{7}\sqrt{7}}{\sqrt[6]{7^5}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%5B3%5D%7B7%7D%5Csqrt%7B7%7D%7D%7B%5Csqrt%5B6%5D%7B7%5E5%7D%7D%20%20%20%20%20)
we can write it in terms of exponents

Firstly , we will simplify numerator

now, we can add exponents

we can cancel it
and we get
............Answer
If we just have

that's an amplitude of 1 and a period of 
Let's modify this step by step.
Amplitude of 4. Four times the amplitude means a factor of 4 on the outside.

Period of π. Double the period means a factor of 2 on the inside.

Horizontal shift of π/2 to the left. To the left means adding a positive number to x. The question appear ambiguous. It's not clear to me if we add to x or 2x; let's make it

Vertical shift of 3:


Depending on the interpretation of the phase shift, that pi may be a pi/2.
Answer: 