Ok so lets say we have a system of equations:
y = x + 1
x + y = 5
All you would do is plug in what is equal to the variable so:
x + x + 1 = 5
Then you would just simplify and solve
2x + 1 = 5
-1 -1
_________
2x = 4
-- --
2 2
x=2
Answer: Tresury department
Step-by-step explanation:
A^2 + b^2 = c^2....a and b are ur legs and c is ur hypotenuse
18^2 + 80^2 = c^2
324 + 6400 = c^2
6724 = c^2
sq rt 6724 = c
82 = c.....so the hypotenuse is 82 cm
Using the normal distribution, it is found that the score needed to qualify is of 88.32.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by
and
.
The top 15% of the applicants are selected, hence the score needed to qualify is the 85th percentile, which is X when Z = 1.04, hence:


X - 80 = 1.04(8)
X = 88.32.
The score needed to qualify is of 88.32.
More can be learned about the normal distribution at brainly.com/question/24663213