Firstly, from the diagram we are given that the length of XB is congruent to BZ, and YC is congruent to CZ. Based on this information, we know that B is the midpoint of XZ, and C is the midpoint of YZ. This means that BC connects the midpoints of segments XZ and YZ. Now that we know this, we can use the Triangle Midsegment Theorem to calculate the length of BC. This theorem states that if a segment connects the midpoints of two sides of a triangle, then the segment is equal to one-half the length of the third side. In this scenario, the third side would be XY, which has a length of 12 units. Therefore, the length of BC = 1/2(XY), and we can substitute the value of XY and solve this equation:

BC = 1/2(XY)

BC = 1/2(12)

BC = 6

Step-by-step explanation:

Please support my answer.

6 0

2 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F

Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ ---> $\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ ---> $\frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x)$ --> $\frac{12}{(3x - 1)(-3x + 2)}$

Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

$Q(x) = \frac{6}{-3x + 2}$

Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

$\frac{2}{3x - 1}*\frac{-3x + 2}{6}$

$\frac{2(-3x + 2)}{6(3x - 1)}$

$= \frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$