Since you didn't provide the points, we can't find the exact answer. However, I can explain how to do the problem for you.
To test the point, just plug in the x and y values and see it the statement is true or false.
Let's try: (3, 4)
Plug in the points and evaluate:
2(4) = 2 + 3
8 = 6
FALSE
Since this is a false statement, then the point is not on the line.
Answer:
17 times
Step-by-step explanation:
IIIinois : 12670000
Alaska : 731545
12670000/731545=17.31
The equations have been computed below
<h3>How to illustrate the information?</h3>
3(x + 2) + 11 = 5(x - 4)
3x + 6 + 11 = 5x - 20
Collect like terms
3x - 5x = -20 - 17
-2x = -37
x = 37/2
x = 18.5
6x + 4 = 3(3 - 2x)
6x + 4 = 9 - 6x
Collect like terms
6x + 6x = 9 - 4
12x = 5.
x = 5/12
Learn more about equations on:
brainly.com/question/2972832
#SPJ1
Step-by-step explanation:
Info : 2^(6)=64
then
64^(1÷4) = (2^(6))^(1÷4)
=2^(6÷4)
=2^(3÷2)
=2√(2)
=2.828427124746
The answer:
the main formula of the circle's equation is
(x-a)²+ (y-b)² = R²
where C(a, b) is the center of the circle
R is the radius
if a point A(x', y') passes through the circle, so the equation of the circle can be written as
(x'-a)²+ (y'-b)² = R², and that is a main formula.
<span>Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2), so we have exactly three equation:
</span>
(0-x)² + (0-y)² = R², circle O passes through A
x²+y²= R²
(-3 -x)² + (0-y)² = R², circle O passes through B
(-3 -x)² + (y)² = R²
(1-x)² + (2-y)² = R², circle O passes through A
(1-x)² + (2-y)² = R²
and we know that R= OA = OC= OB,
OA=R= sqrt( (0-x)² + (0-y)² ) = OB = sqrt((-3 -x)² + (0-y)²), this implies
x²+y² = (-3 -x)² + (0-y)² , it implies x² = 9+ x² + 6x , and then -9/6=x, x= -3/2
and when OA = OC
x²+y² =(1-x)² + (2-y)² so, x²+y² =1+x²-2x +4+y²-4y, therefore -5= -2x -4y
-5= -2x -4y, when x = -3 /2 we obtain y = 2
the center is C(-3/2, 2)
