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3 years ago

A and b please on #2

Mathematics

1 answer:

Neporo4naja [7]3 years ago

6 0

Answer:

1. 9.12

2. 10.64

3. 12.16

b- No it does not because it does not include the 5 pennies that are already there.

Step-by-step explanation:

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Stuck on this question. Any help?

Rashid [163]

Answer:

no 5 7 6

Step-by-step explanation:

8 0

3 years ago

Brett shaded 4/8 of a sheet of notebook paper. Aisha says he shaded 1/2 of the paper. Are the two fractions equivalent? if so, w

kati45 [8]

Answer:

Step-by-step explanation:

6 0

3 years ago

Find the discriminant of the following equation:

vladimir1956 [14]

Option 1

The discriminant of given equation is 116

Solution:

We have to find the discriminant of given equation

Given equation is:

$f(x) = 4x^2+6x-5$

To find discriminant,

$4x^2+6x-5 = 0$

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0$

Discriminant is given by:

$D = b^2-4ac$

On comparing the given quadratic equation $4x^2+6x-5 = 0$ with general quadratic equation $ax^2+bx+c = 0$

a = 4

b = 6

c = -5

Substituting in above formula,

$D = 6^2-4(4)(-5)\\\\D = 36-16(-5)\\\\D = 36+80\\\\D = 116$

Thus discriminant of given equation is 116

8 0

3 years ago

ann has 5 brand new CD’s, which is 3 less than twice the that bob (x) has. translate the situation into an algebraic equation

Nataliya [291]

Ann = 3 CD's

Ann = 2x-3

5 = 2x-3

x= CD's bob has

5 = 2x-3 is the equation

to solve

add 3 to each side

8 = 2x

divide by 2

x =4

bob has 4 CD's, ann has 5

6 0

3 years ago

WILL MARK BRAINLIEST!!! Given p(x)=x3−4x2+15x+k and the remainder of the division of p(x) by (x+1) is equal to −8, what is the r

balandron [24]

Use the polynomial remainder theorem. If $p(x)$ is a polynomial of degree $n>1$ , then we can divide by a linear term $x-c$ to get a quotient $q(x)$ and remainder $r(x)$ of the form

$\dfrac{p(x)}{x-c}=q(x)+\dfrac{r(x)}{x-c}\iff p(x)=(x-c)q(x)+r(x)$

Then when $x=c$ , we get $p(c)=r(c)$ . In other words, the value of $p(x)$ at $x=c$ tells you the value of the remainder upon dividing $p(x)$ by $x-c$ .

So given that $p(x)=x^3-4x^2+15x+k$ , and the remainder upon dividing $p(x)$ by $x+1$ is -8, we know that $r(-1)=-8$ , so

$\dfrac{x^3-4x^2+15x+k}{x+1}=q(x)-\dfrac8{x+1}$
$\dfrac{x^3-4x^2+15x+k+8}{x+1}=q(x)$

Since $q(x)$ is a polynomial (not a rational expression), then we know that $x+1$ divides $x^3-4x^2+15x+k+8$ exactly. In particular, the remainder term of this quotient is 0. We can use long or synthetic division to determine $q(x)$ . I prefer typing out the work for synthetic division:

-1   |   1   -4   15    k + 8
.     |        -1     5       -20
- - - - - - - - - - - - - - - - - -
.     |   1   -5    20    k - 12

The remainder here has to be 0, so $k-12=0\implies k=12$ .

Finally, we can get the remainder upon dividing $p(x)$ by $x-1$ by evaluating $p(1)$ , which gives $p(1)=24$ .

6 0

3 years ago

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