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Mandarinka [93]
3 years ago
5

Find a formula for the nth term an=4n+?

Mathematics
1 answer:
zepelin [54]3 years ago
5 0
<span>I tried a formula with Tn+1, swapped in 4n-2 for 4(n+1)-2 = 4n+4 and then proceeded with Tn+1 + Tn = 4n+2 - 4n-2.

</span>
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A store is having a sale on almonds and jelly beans. For 2 pounds of almonds and 5 pounds of jelly beans, the total cost is $17
Mariulka [41]
I think it would be $16 :)
4 0
3 years ago
Nate is exponentially gaining Twitter followers! His current amount of followers is 146. His followers are increasing at a 24% r
tia_tia [17]

Answer:

(a) Growth

(b)\ y = 146(1.24)^x

Step-by-step explanation:

Given

a= 146 -- current

r = 24\% --- rate

Solving (a): Growth or decay

The question says his followers increases each day by 24%.

Increment means growth.

<em />

<em>Hence, it is a growth problem</em>

Solving (b): Equation to represent the scenario.

Since the rate represents growth, the equation is:

y = a(1 + r)^x

Substitute: a= 146 and r = 24\%

y = 146 * (1 + 24\%)^x

y = 146 * (1 + 0.24)^x

y = 146 * (1.24)^x

y = 146(1.24)^x

5 0
3 years ago
20 Points Please help me
solong [7]

Answer:

98 inches

Step-by-step explanation:

Multiply the top length by the bottom length

4 0
2 years ago
Can someone help me please ​
andrey2020 [161]

Answer: y = 6

Step-by-step explanation:

A square's area can be done by using s^2, where s is y in this case.  Because there are 5 squares, the area of the figure is 5y^2.  Because the area is also 180cm, 5y^2=180.

Then divide both sides of the equation by 5 to get y^2 = 36.  Then square root both sides of the equation to get y = 6.

Hope it helps <3

7 0
3 years ago
Given: A, B, and C What is the value of X in the matrix equation AX + B = C?
Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

7 0
3 years ago
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