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Over [174]
3 years ago
15

1) Given that lines L and M are parallel, which of the statements is true? A) ∠ DEF ≅ ∠ EBC B) ∠ ABC ≅ ∠ DEF C) ∠ ABC ≅ ∠ EBC D)

∠ BEF ≅ ∠ ABC
Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0
Cant do anything without the picture of the lines
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List from least to greatest <br> 3.87 3 1/2 5
nexus9112 [7]
The least to greatest is 3 1/2, 3.87 and 5 since you need to use teh decimal placements to find out the answer.

4 0
3 years ago
Two circles with different radii have chords AB and CD, such that AB is congruent to CD. Are the arcs intersected by these chord
emmainna [20.7K]

The arcs intersected by these chords are not congruent.

Given that two circles with different radii have chords AB and CD, such that AB is congruent to CD.

Let r₁ and r₂ be the radii of two different circles with centers O and O' respectively.

Assuming that the each of the ∠АОВ  and ∠CO'D is less than or equal to π.

Then, we have isosceles triangle AOB and CO'D such that,

AO = OB = r₁,

CO' = O'D = r₂,

Let us assume that r₁< r₂;

We can see that arc(AB) intersected by AB is greater than arc(CD), intersected by the chord CD;

arc(AB) > arc(CD)      .......(1)

Indeed,

arc(AB) = r₁ angle (AOB)

arc(CD) = r₂ angle (CO'D)

So, we have to prove that ;

∠AOB >∠CO'D       ......(2)

Since each angle is less than or equal to π, and so

∠AOB/2  and ∠CO'D/2 is less than or equal to π

it suffices to show that :

tan(AOB/2) >tan(CO'D/2) ......(3)

From triangle AOB :

tan(AOB/2) = AB/(2*r₁)

tan(CO'D/2) = CD/(2*r₂)

Since AB = CD and r₁ < r₂ (As obtained from the result of (3) ), therefore, arc(AB) > arc(CD).

Hence, for two circles with different radii have chords AB and CD, such that AB is congruent to CD but the arcs intersected by these chords are not congruent.

Learn more about congruent from here brainly.com/question/1675117

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6 0
2 years ago
Determine whether the set is finite ir infinite
STatiana [176]

Answer:

The set is <u>Infinite</u>

Step-by-step explanation:

Infinite sets are ≥ greater than 1 and sometimes has an <u>N</u>

5 0
2 years ago
Indiras spring garden has half as many tulips as daffodils and three times as many hyacinths as tulips. If there are a total of
kow [346]

Indira is having 34 tulips, 68 daffodils and 102 hyacinths , altogether 204 flowers in her spring garden.

Given, In Indira's springtime garden, there are three times more hyacinths than tulips and half as many daffodils as tulips.

let the number of tulips be = x

    the number of daffodils be = y

    the number of hyacinths be = z

hence according to the question,

tulips are (x) = 1/2 (y) = y/2

hyacinths are (z) = 3(x) = 3x

therefore, total flowers = 204

tulips ₊ daffodils ₊ hyacinths = 204

y/2 ₊ y ₊ 3x = 204

substitute x value in the above equation.

y/2 ₊ y ₊ 3(y/2) = 204

take LCM

y ₊ 2y ₊ 3y = 408

6y = 408

y = 408/6

y = 68

hence the number of daffodils is 68.

now substitute y value in x = y/2

x = 68/2

x = 34

now substitute x value in z= 3x

z = 3(34)

z = 102

hence we get the number of tulips,daffodils and hyacinths as 34 , 68 and 102 respectively.

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6 0
1 year ago
For water to be a liquid, its temperature must be within 50 Kelvin of 323 Kelvin. Which equation can be used to determine the mi
Margarita [4]

Answer:

Mark as BRAINLIEST plz

|x-323|<50: answer

Step-by-step explanation :

For water to be a liquid, the temperature must be within 50 Kelvin of 323 K.

So, the range of the temperature of water will lie between 50 kelvin more than 323 kelvin and 50 kelvin less than 323.

The equation that can be used to determine the maximum temperature at which water is a liquid can be given by :  x < 323 + 50

The equation that can be used to determine the minimum temperature at which water is a liquid can be given by : x > 323 - 50

So the resultant equation can be written as :

|x-323|<50

8 0
4 years ago
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