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tensa zangetsu [6.8K]
3 years ago
9

I am a famous black mathematician whos work is in biomathematics, genetic variation and chaos theory. Who am I?

Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0

The answer is Fern Hunt

baherus [9]3 years ago
3 0

Answer: Fern Hunt

Step-by-step explanation: I think that is correct

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Find the nth term: 8, 18, 28, 38, 48....
Ivanshal [37]

Answer:

The ninth term? That would be 98.

Step-by-step explanation:

Notice how the numbers add 10 every time. If we keep doing that pattern until we get the ninth number, then we get this:

8, 18, 28, 38, 48, 58, 68, 78, 88, 98

Therefore, the answer is 98.

7 0
3 years ago
Pls help.................
Crank
The correct answer is u multiple it by 5 then u move it directions
7 0
3 years ago
Read 2 more answers
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
4 years ago
If a quadratic function has x-intercepts at 2 = -
PolarNik [594]

Complete question is;

If a quadratic function has x-intercepts at x = -3 and x = -1, one possible equation of the function would be y = (x + 3)(x + 1), a graph that first

decreases until it reaches the vertex, (-3, -1), then increases (opening upward U shape).

So then, if a quadratic function has x-intercepts at x = -2 and x = 2

a. What is the equation of this quadratic function? Explain your reasoning

b. What is the vertex of the equation? Show your work and explain your reasoning.

Answer:

Quadratic equation is; y = x² - 4

Vertex: (0, -4)

Step-by-step explanation:

The x-intercepts are at x = -2 and x = 2. Thus, the equation is;

y = (x - (-2))(x - 2)

y = x² + 2x - 2x - 4

y = x² - 4

Now,the coordinates of the vertex will be (h, k)

Where;

h = -b/2a

k is the value of y at x = h

From y = x² - 4, h = 0

Thus, putting x = h = 0 in the quadratic equation, we have;

y = 0² - 4

y = -4

Thus,the coordinates of the vertex are; (0, -4)

3 0
3 years ago
I need help. due today
just olya [345]
X = 19.

Explanation:

This expression is vertical from the angle 135, meaning it is congruent. With that being said, we would need to find what 7 multiplies by to give us 2 less than 135, which would be 133. Because 133 divided by 7 equals 19, x = 19. If we plug this in, we get the following equation: 7(19) + 2 = 135.
6 0
2 years ago
Read 2 more answers
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