Question

A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf produced in the wire is 0.45 volts. What is the magnetic field strength? A. 0.034 newtons/amp·meter B. 0.17 newtons/amp·meter C. 0.26 newtons/amp·meter D. 0.77 newtons/amp·meter E. 6.0 newtons/amp·mete

Answer 1

Answer:

Magnetic field strength, $B=6\ N/A-m$

Explanation:

Given that,

Length of the wire, l = 0.36 m

Speed with which the wire moves in a magnetic field, v = 0.21 m/s

The induced emf produced in the wire is 0.45 volts, $\epsilon=0.45\ V$

It is a case of motional emf. When a wire moves in a magnetic field with velocity v, an emf is induced in the wire. It is given by :

$\epsilon=Blv$

B is the magnetic field strength

$B=\dfrac{\epsilon}{lv}$

$B=\dfrac{0.45\ V}{0.36\ m\times 0.21\ m/s}$

$B=5.95\ N/A-m$

or

$B=6\ N/A-m$

So, the magnetic field strength is 6 N/A. Hence, this is the required solution.

Answer 2

Answer:

B= magnetic field strength

Explanation:

use formula E = Blv

l=length

v=speed

this works if field &wire carrying current is perpendicular only

make sure you get your units right