Answer:
50% of students have a GPA higher than 3.1.
Step-by-step explanation:
We are given that the mean GPA of students in a neighboring school is 3.1 with a standard deviation of 0.3.
Assuming that the data follows normal distribution.
<u><em>Let X = GPA of students in a neighboring school</em></u>
So, X ~ Normal()
The z score probability distribution for normal distribution is given by;
Z = ~ N(0,1)
where, = population mean GPA = 3.1
= standard deviation = 0.3
Now, the probability that the students have a GPA higher than 3.1 is given by = P(X > 3.1)
P(X > 3.1) = P( >
) = P(Z > 0) = 0.50
<em>The above probability is calculated by looking at the value of x = 0 in the z table which has an area of 0.50.</em>
Therefore, 50% of students have a GPA higher than 3.1.