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3 years ago

If two pounds of peaches are 4.20 how much is five pounds

2 answers:

5 0

The first step would be to divide 4.2 by 2 to find how many are 1 pound 4.2/2=2.1. then multiply that new number by 5 to get the total 2.1x5=10.5. thus the answer would be 5 pounds of peaches are 10.5

Anastaziya [24]3 years ago

4 0

$2p......4.20\$ \\5p.........x \\\\ x=\frac{5*4.20}{2} \\\\ x=5*2.10 \\\\ \boxed{x=10.50\$}$

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A survey was taken among a group of people. The probability that a person chosen likes Italian food is 0.75, the probability tha

Luda [366]

Answer:

54% probability that a person likes Italian food, but not Chinese food.

82% probaility that a person likes at least one of these foods

79% proability that a person likes at most one of these foods

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a person likes Italian food.

B is the probability that a person likes Chinese food.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a person likes Italian food but not Chinese and $A \cap B$ is the probability that a person likes both Italian and Chinese food.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that a person likes both foods is 0.21.

This means that $A \cap B = 0.21$

The probability that a person likes Chinese food is 0.28

This means that $B = 0.28$

$B = b + (A \cap B)$

$0.28 = b + 0.21$

$b = 0.07$

The probability that a person likes Italian food is 0.75

This means that $A = 0.75$

$A = a + (A \cap B)$

$0.75 = a + 0.21$

$a = 0.54$

Determine the probability that a person likes Italian, but not Chinese

This is a.

54% probability that a person likes Italian food, but not Chinese food.

Determine the probaility that a person likes at least one of these foods

$P = a + b + (A \cap B) = 0.54 + 0.07 + 0.21 = 0.82$

82% probaility that a person likes at least one of these foods

Determine the proability that a person likes at most one of these foods

Either a person likes at most one of these foods, or it likes both. The sum of the probabilities of these events is decimal 1.

0.21 probability it likes both.

Then

0.21 + p = 1

p = 0.79

79% proability that a person likes at most one of these foods

6 0

3 years ago

Can someone please help me??

Ira Lisetskai [31]

I believe its the 4th option

Im not sure

I hope i helped

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3 years ago

Samantha is making some floral arrangements.The table shows the prices for packs of six of each type of flower.

belka [17]

Okay so the first thing we should do here is round 5.29 rounds to 5.30 3.59 rounds to 3.60 and 4.79 rounds to 4.80 now add all of those up youll get 13.7 you can round that to 14 so samanthas estimate is accurate

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3 years ago

Will mark brainlist

vladimir2022 [97]

Answer:

n-17

Step-by-step explanation:

3 0

3 years ago

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In a boaster club,1/8 of the 128 members are men how many male member are in the club

Bingel [31]