Answer:
B $240.00
Step-by-step explanation:
thats the correct answer
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
.725 multiplied by 4500=362.5
750+3262.5=4012.5
Answer:
$1,700
Step-by-step explanation:
Given the following :
Period of mortgage = 25 years
Mortgage amount = $130,000
Total interest on mortgage = $380,000
Hence,
Total amount to be paid ( principal + interest) :
($130,000 + $380,000) = $510,000
Total number of months over the 25 years period:
25 × 12 = 300 months
Payment per month:
Total repayment / number of months
= $510,000 / 300
= $1,700 per month
Answer:
w(C(L))= 0.25 |L - 105|
Step-by-step explanation:
you plug in C(L) into L in w(L)
