Can someone help me understand Slope-Intercept Form for algebra please???

Mathematics

2 answers:

Katena32 [7]3 years ago

3 0

Answer:

the equation of a straight line in the form y = mx + b where m is the slope of the line and b is its y-intercept.

Step-by-step explanation:

yarga [219]3 years ago

3 0

Answer:

the slope intercept form is

Step-by-step explanation:

Algebra 1 - y=mx+b

Algebra 2 - y=mx+b

m=slope

(0, b)=y-intercept

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Ksju [112]

Answer:

(-9.5, 6.75)

Step-by-step explanation:

I inputted both equations on the desmos website and they met at this point

8 0

3 years ago

0.00592 to 4 decimal places

Leya [2.2K]

0.00592 ≈ 0.0059 to 4 decimal places.

The number after the fourth decimal place is 2, and this is not up to 5, so we round down.

6 0

3 years ago

Read 2 more answers

Find the slope intercept form.<br><br>passes through the points (4,3) and (7,-2)

11111nata11111 [884]

$(\stackrel{x_1}{4}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{-2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{4}}} \implies \cfrac{-2 -3}{7 -4} \implies \cfrac{ -5 }{ 3 }$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-\cfrac{5}{3}}(x-\stackrel{x_1}{4}) \\\\\\ y-3=-\cfrac{5}{3}x+\cfrac{20}{3}\implies y=-\cfrac{5}{3}x+\cfrac{20}{3}+3\implies y=-\cfrac{5}{3}x+\cfrac{29}{3}$