Answer:
Dy/Dx=x
(
2
ln
(
x
)
−
1
)/
ln
^2
(
x)
Step-by-step explanation:
We have this function and let's derive it in terms of x.
y =x^2/In x
Dy/Dx=(x^2/In x)'=2/lnx *(x^2)'-(x^2/In x)'=> 2
x
*ln
(
x
)
−
x
*ln
^2
(
x
)
=x
(
2
ln
(
x
)
−
1
)/
ln
^2
(
x)
Answer:
Sample answer: The median of the means for Grade 8 is greater than for Grade 12. However, there is less variation in the data for Grade 12 since the length of the box for Grade 12 is shorter than the one for Grade 8.
Answer:
the slope in the equation is 5, while the slope on the graph is 2
120 ft... a flat vertical line is 180 degrees, and since this is a 30,60,90 triangle, your equation is... 180-60=distance John is to the base
2x^3 + 9x - 8 - (4x^2 - 15x + 7)....distribute thru the parenthesis
2x^3 + 9x - 8 - 4x^2 + 15x - 7....combine like terms
2x^3 - 4x^2 + 24x - 15 <==
