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Temka [501]
2 years ago
15

Please help!

Mathematics
1 answer:
Yuki888 [10]2 years ago
3 0

Answer:

3

Step-by-step explanation:

You might be interested in
If one rooster can wake up 10 hens, then how many hens can 3 roosters wake up?
Tresset [83]
I’m pretty sure the answer is 30... right? Because you’d multiply 10 and 3
3 0
3 years ago
A tree farm owner uses a grid to mark where to plant trees in the spring. The first tree is planted at (2, 3). Each of the other
Tatiana [17]

Answer:

See attached image for the drawing of the first four trees (circled in green)

The patterns is:

x = 2+3n  and  y= 3+2n

Position of 7th tree is: (20,15) (circled in orange in the image)

Step-by-step explanation:

Starting at the location (2,3) the next x and y positions are given by:

x = 2+3n since the horizontal position needs to be increased by 3 units on each iteration,

and y= 3+2n since the vertical position needs to be increased by 2 units on each iteration

being n= 1 through 6 (to account for the next 6 trees that need to be planted)

With such pattern, the location of the seventh tree would be:

x = 2 + 3*6 =2 + 18 = 20

y = 3 + 2*6 = 3 + 12 = 15

That is, the point (20,15) on the plane.

Also see attached image.

8 0
3 years ago
Due in 1 hour, plz help
snow_lady [41]

Answer:

1. 12/1= rate of change

Step-by-step explanation:

1.

1 mile= 30 seconds

(1,30)

6 miles= 1 1/2 minutes

6 miles=90seconds

(6,90)

Formula: y2-y1/x2-x1

90-30/6-1

60/5

12/1= rate of change

hope its right

3 0
2 years ago
Ms Happy has decided to start wearing a face mask, because it is now required of her to do so. The mask she has started wearing
Alchen [17]

Answer:

37.20 %

Step-by-step explanation:

Circumference = 2 × pi × r

30 = 2 × 3.14 × r

r = 4.7770700637

Area of her face = pi × r²

3.14 × 4.7770700637²

= 71.6560509556 in²

Area of the mask = 9 × 5 = 45 in²

Uncovered area

= 71.6560509556 - 45

= 26.6560509556 units²

% of uncovered area:

26.6560509556/71.6560509556 × 100

37.2%

6 0
3 years ago
Two objects were lifted by a machine. One object had a mass of 2 kilograms and was lifted at a speed of 2m/sec. the other had a
OLga [1]
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:

<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
     potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.

<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
     potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.

If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.

4 0
3 years ago
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