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Temka [501]
2 years ago
15

Please help!

Mathematics
1 answer:
Yuki888 [10]2 years ago
3 0

Answer:

3

Step-by-step explanation:

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What is the pattern as the exponents decrease?
Nana76 [90]
Can we see the patern please
4 0
3 years ago
Hey I have a link to the question since its kinda complicated
Natalija [7]
Anyway

so the recursive rule tells the relationship between the previous term and the term we want to find

given

an=2n+11
it is clear that the first term is 13
2nd term is 15
3rd term is 17

each term increases by 2
so
a term is equal to the previous term plus 2
an=a(n-1)+2

the first one is the answer
8 0
3 years ago
Read 2 more answers
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
2 years ago
The center is (0, -3.2) and the radius is 2.2.
Radda [10]

Answer:

x^{2} +(y+3.2)^{2} =2.2^{2}

Step-by-step explanation:

(x-h)^{2} +(y-k)^{2} =r^{2}

The center is (h, k)

r is the radius

4 0
3 years ago
What two numbers are the absolute value of 4
kati45 [8]
The absolute value is the distance from 0, so it would be 4 and -4
5 0
3 years ago
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