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lawyer [7]
3 years ago
13

What is the solution set for the quadratic inequality 4(x+2)^2<0

Mathematics
2 answers:
JulsSmile [24]3 years ago
6 0

What is the solution set for the inequality?

(–∞, 2]

(–∞, 34/9 ]

[2, ∞)

[34/9, ∞)

Answer:

A. (–∞, 2]

photoshop1234 [79]3 years ago
5 0
Hope this can help you

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Type the correct answer in each box. Use numerals instead of words.
Natali5045456 [20]

Given:

Consider the given function is f(x)=-(x+1)(x-3)(x+2).

To find:

The remaining zero and y-coordinate of y-intercept.

Solution:

We have,

f(x)=-(x+1)(x-3)(x+2)

For zeros, f(x)=0.

-(x+1)(x-3)(x+2)=0

(x+1)(x-3)(x+2)=0

(x+1)=0,(x-3)=0,(x+2)=0

x=-1,x=3,x=-2

So, three zeros of given function are -1, 3 and -2.

Putting x=0 in the given function, we get

f(0)=-(0+1)(0-3)(0+2)

f(0)=-(1)(-3)(2)

f(0)=-(-6)

f(0)=6

So, the y-coordinate of y-intercept of the given function is 6. It means the y-intercept is at point (0,6).

Therefore, the zeros of the function f(x)=-(x+1)(x-3)(x+2) are –1, 3, and -2 and the y-intercept of the function is located at (0,6).

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