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2 years ago

ANSWER PLZ QUICK AND FAST

Mathematics

1 answer:

OverLord2011 [107]2 years ago

7 0

A a numerical expression

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Which of the following data sets has the mean, median, mode, and range as the same number?

I am Lyosha [343]

Answer:

Step-by-step explanation:

6, 11,14,14,19,20

Adding these 6 numbers we get 84.

84 / 6 = 14 = mean.

Median = middle number(s) = 14

Mode = number occurring most = 14.

5 0

1 year ago

Please help me out!!!

serg [7]

Answer:

x = 76.9

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp side / adj side

tan 70 = x/28

28 tan 70 = x

x=76.92936

Rounding to the nearest tenth

x = 76.9

8 0

2 years ago

Read 2 more answers

Y=arccos(1/x) Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

1 year ago

The quotient of -24 and the sum of p and q

boyakko [2]

Answer:

the sum of p and q is pXq =pq

4 0

2 years ago

Solve. 5 3 + 8 4 -2 5 3 6 21 - -2 16 Done

kondor19780726 [428]

Answer:

2 1/16

Step-by-step explanation:

Hope this Helps! :)

7 0

2 years ago