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Oksi-84 [34.3K]

3 years ago

6

A skier has decided that on each trip down a slope, she will do 2 more jumps than before. On her first trip she did 6 jumps. Der

ive the sigma notation that shows how many total jumps she attempts from her fourth trip down the hill through her twelfth trip. Then solve for the number of total jumps from her second to tenth trips.

1 answer:

Lady_Fox [76]3 years ago

5 0

<span><span>∑<span>i=2</span><span>i=10</span></span>(4+2n)=</span><span> You can do it by hand, w/o much work . plug in n=2 into (4+2n) then plug in n=3 into (4+2n) then plug in n=4 into (4+2n) etc until you get to n=10. Add them all up.
</span><span>add 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22 + 24
</span><span>144 jumps!</span>

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Answer:

2 5/8 inches

Step-by-step explanation:

There are 2 pieces 5 3/4 inches long.

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There are 4 pieces 5 1/4 inches long.

The seventh longest piece is one of the pieces measuring 5 1/4 inches.

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2 years ago

A sample of 100 is drawn from a population with a proportion equal to 0.50. Determine the probability of observing between 43 an

diamong [38]

Answer:

The probability of observing between 43 and 64 successes=0.93132

Step-by-step explanation:

We are given that

n=100

p=0.50

We have to find the probability of observing between 43 and 64 successes.

Let X be the random variable which represent the success of population.

It follows binomial distribution .

Therefore,

Mean, $\mu=np=100\times 0.50=50$

Standard deviation , $\sigma=\sqrt{np(1-p)}$

$\sigma=\sqrt{100\times 0.50(1-0.50)]$

$\sigma=5$

Now,

$P(43\leq x\leq 64)=P(42.5\leq x\leq 64.5)$

$P(42.5\leq x\leq 64.5)=P(\frac{42.5-50}{5}\leq Z\leq \frac{64.5-50}{5})$

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$P(42.5\leq x\leq 64.5)=P(Z\leq 2.9)-P(Z\leq- 1.5)$

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$P(43\leq x\leq 64)=0.93132$

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2 years ago

I need help graphing 2x-5y=5

viktelen [127]

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3 years ago

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yawa3891 [41]

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3 years ago

BRAINLIEST..........show expressions too<333

vovikov84 [41]

Answer:

9.) $t=.05m+20$

10.) $t=.10m+5$

11.) $300$ minutes of calling would make the two plans equal.

12.) Company B.

Step-by-step explanation:

Let <em>t</em> equal the total cost, and <em>m,</em> minutes.

Set up your models for questions 9 & 10 like this:

<em>total cost = (cost per minute)# of minutes + monthly fee</em>

Substitute your values for #9:

$t=.05m+20$

Substitute your values for #10:

$t=.10m+5$

__

To find how many minutes of calling would result in an equal total cost, we have to set the two models we just got equal to each other.

$.10m+5=.05m+20$

Let's subtract $5$ from both sides of the equation:

$.10m=.05m-15$

Subtract $.05m$ from both sides of the equation:

$.05m=15$

Divide by the coefficient of $m$ , in this case: $.05$

$m=300$

__

Let's substitute $200$ minutes into both of our original models from questions 9 & 10 to see which one the person should choose (the cheaper one).

Company A:

$t=.05(200)+20$

Multiply.

$t=10+20$

Add.

$t=30$

Company B:

$t=.10(200)+5$

Multiply.

$t=20+5$

Add.

$t=25$

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6 0

3 years ago