Answer: oops 375 idk what happend
Step-by-step explanation:
tysm
the height of the house is 
.
<u>Step-by-step explanation:</u>
Here we have , To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to the top of the house was 32 degrees. Katie then moved 200 feet closer to the house along a level street and determined the angle of elevation was 42 degrees. We need to find What is the height of the house . Let's find out:
Let y is the unknown height of the house, and x is the unknown number of feet she is standing from the house.
Distance of house from point A( initial point ) = x ft
Distance of house from point B( when she traveled 200 ft towards street = x-200 ft
Now , According to question these scenarios are of right angle triangle as
At point A
⇒ 
⇒ 
⇒ 
..................(1)
Also , At point B
⇒ 
⇒ 
..............(2)
Equating both equations:
⇒ 
⇒ 
⇒ 
⇒ 
Putting in we get:
⇒
⇒ 
⇒ 
Therefore , the height of the house is .
Answer:
12 in squared
Step-by-step explanation:
Since the side on the bigger figure is 6 and the smaller figure‘s side is 3, that means the smaller figure is half the size of the big figure.
So.. 24 divided by 2 is 12
The rule for quotients of similar bases with different exponents is:
(a^c)/(a^b)=a^(c-b) in this case:
15^18/(15^3)=15^15
This is the easiest way to solve this problem:
Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __
For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations
For the next two do the same process as the one above.
If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations
If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.
<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>
10*9*9*9 = 7290 combinations
