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Readme [11.4K]
3 years ago
12

Which equation shows 6 as the constant of proportionality

Mathematics
1 answer:
ikadub [295]3 years ago
5 0
Do you mind showing the whole graph to the left?
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Expand the following 2(x+3)
Maksim231197 [3]

Answer:

2x + 6

Step-by-step explanation:

2 will multiply everything inside the bracket.

2 x X =2x

2 X 3=6

6 0
3 years ago
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I need help with this question!
KonstantinChe [14]
F(x)=2x^4 is the answer
5 0
3 years ago
Hello again. if someone gives me a hand with this book thickness excercise please thanks
geniusboy [140]

Answer:

Known:

• a book have front, back and 200 pages

• front= 0.7 mm

• back= 0.7 mm

• each page= 0,14 mm

ask:

calculate the minimum thickness...?

answer:

a. 200 p × 0,14 = 28 mm

b. front + back = 0.7+0.7= 1.4 mm

Thickness= 28+1,4 = 29,4 mm

I hope this helps

if u have question let me know in comments^_^

8 0
4 years ago
Select the basic integration formula you can use to find the indefinite integral.
kondaur [170]

Answer:

\int \dfrac{du}{u}=\log|u|+C

\int u^n du=\dfrac{u^{n+1}}{n+1}+C

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C

Step-by-step explanation:

a.

\int \dfrac{du}{u}=\log|u|+C    [\because \int \dfrac{dx}{x}=\log |x|+C]

b.

\int u^n du=\dfrac{u^{n+1}}{n+1}+C    [\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]

c.

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C        [\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]

3 0
4 years ago
What is the area of this figure​
MAVERICK [17]

Answer:

57

Step-by-step explanation:

7-3=4

3x4=12/3=4

do that two times because there is two triangles

7x7=49

4+4+49=57

8 0
4 years ago
Read 2 more answers
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