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yKpoI14uk [10]
3 years ago
8

Anyone know this ? i am having trouble today lol

Mathematics
1 answer:
svetlana [45]3 years ago
8 0
The park are 4 units apart. 

Hope this helps :)
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Geometry Help ! Look at the picture
OLEGan [10]

Pyhtaorean theorem says a² + b² = c²

a² + 7² = 25²

a² + 49 = 625; subtract 49 from both sides

a² = 576; square root both sides

a = 24

The perimeter is the distance around the figure, so 7 + 24 + 25 or 56

7 0
3 years ago
Which of the following in an identity?
sammy [17]
By "which is an identity" they just mean "which trigonometric equation is true?"

What you have to do is take one of these and sort it out to an identity you know is true, or...

*FYI: You can always test identites like this:
Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
sinx = 3/5    cscx = 5/3
cosx = 4/5   secx = 5/4
tanx = 4/3    cotx = 3/4
Then just plug them in and see if it works. If it doesn't, it can't be an identity!

Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.

Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)

Next is b. Here we have (cscx + cotx)² = 1. Let's take the square root of each side...cscx + cotx = 1. Now you should be able to see why this can't work as a Pythagorean Identity. There's always that test we can do for verification...5/3 + 3/4 ≠ 1, nor is (5/3 +  3/4)².

By process of elimination, a must be true. You can test w/ our example ratios:
sin²xsec²x+1 = tan²xcsc²x
(3/5)²(5/4)²+1 = (4/5)²(5/3)²
(9/25)(25/16)+1 = (16/25)(25/9)
(225/400)+1 = (400/225)
(9/16)+1 = (16/9)
(81/144)+1 = (256/144)
(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
5 0
3 years ago
Pls help me to understand TwT ive been struggling oof.
klio [65]

Step-by-step explanation:

The surface area of a square pyramid is the area of the square base plus the area of the 4 lateral faces:

A = b² + 4 (½ bl)

A = b² + 2 bl

where b is the width of the base,

and l is the slant height.

6 0
4 years ago
Read 2 more answers
If sin theta =1/4, theta in quadrant II, find the exact value of cos[theta +pi/6]
Mashcka [7]
Using cos addition formula:
use x for theta
cos(x+π/6)=cosx*cos(π/6)-sinx*sin(π/6)
sinx=1/4
cosx=√15/4
cos(π/6)=√3/2
sin(π/6)=1/2
cos(x+π/6)=(√15/4*√3/2)-(1/4*1/2)
cos(x+π/6)=(√45/8)-(1/8 )
cos(x+π/6)=(√45-1)/8)
6 0
3 years ago
Sarah is taking a test. The test is designed to produce an overall mean score of 85 with a standard deviation of 5 for all test
Arturiano [62]

Answer:

Option D)

The area below the standardized test score is 0.8413

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 85

Standard Deviation, σ = 5

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(score is below 90)

P( x < 90) = P( z < \displaystyle\frac{90 - 85}{5}) = P(z < 1)

Calculation the value from standard normal z table, we have,  

P(x < 90) =0.8413 = 84.13\%

Thus, the correct answer is

Option D)

The area below the standardized test score is 0.8413

4 0
3 years ago
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