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3 years ago

Write an integer for each situation. 3 miles below sea level u may solve the other ones?

Mathematics

2 answers:

Evgen [1.6K]3 years ago

6 0

"3 miles below sea level" may be written as -3. The negative indicates you are below sea level. Going above sea level means the value would be positive.

"earning 45 dollars" can be written as +45 or simply 45. If you lost 45 dollars, then it would be -45. If you are in debt 45 dollars, then it would be -45.

"moving back 5 spaces" is represented by -5 whereas moving forward 5 spaces is +5 or simply 5.

Alex Ar [27]3 years ago

6 0

-3

45

-5. Here u go.

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Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result

Vaselesa [24]

Complete Question:

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

Correct Answer:

A) $(10-x)(12-x)=15$

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

Step-by-step explanation:

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

$length=10-x\\breadth=12-x$

According to question , Area of new image is :

⇒ $Area = \frac{1}{8}Length(breadth)$

⇒ $Area = \frac{1}{8}(10)(12)$

⇒ $Area = 15$

So the equation will be :

⇒ $(10-x)(12-x)=15$

b. Find the dimensions of the reduced image

Let's solve : $(10-x)(12-x)=15$

⇒ $120-10x-12x+x^2=15$

⇒ $120-22x+x^2=15$

⇒ $x^2-22x+105=0$

By Quadratic formula :

⇒ $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $x = \frac{22 \pm8 }{2}$

⇒ $x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}$

⇒ $x = 15 , x =7$

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ $x =7$

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

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2 years ago

If anybody now this pls help my homework due TOMORROW

Nezavi [6.7K]

Answer:

Part A: D. $y = (x + 1)(x+3)\\$

Part B: C. $3x(x-3) = 0\\$

Step-by-step explanation:

For part A) we just have to plug in 0 for x and solve for y until we find the equation that says 3 is the value for y when x is 0. For purposes of speeding up the process the correct answer is D. I will show how to check for it now.

The equation: $y = (x + 1)(x+3)$

Now plug in 0 for x.

$y = (0 + 1)(0+3)\\$

Now solve.

y = (1)(3)

y = 3

This proves that this is the correct answer.

For part B) we just have to plug in the give values for x separately and check for each value of x that it equals 0. For the purpose of speeding up the process the correct answer is C. I will show how to check for it now.

The equation: $3x(x-3) = 0$